Performance 检查坐标列表中所有值的最快方法

我有一个坐标列表

a=[（1,2），（1300），（2,3）…]

这些值是

1000 x 1000 NumPy

阵列的面积坐标

假设我要求这些坐标下的所有值的和。有没有比以下更快的方法：

sum([array[i[0],i[1]] for i in a])

---

使用

a

将掩码应用于

数组

，然后对掩码数组求和。例如：

# Prepare sample array and indices
a = np.arange(10*10).reshape(10,10)
ind = [(1,0), (2, 4), (2,6), (7,7), (8,9), (9,3)]

# Cast list of coordinates into a form that will work for indexing
indx = np.split(np.array(ind), 2, axis = 1)

# A warning may be raised about not using tuples for indexing. You can use tuple(indx) to avoid that.
np.sum(a[indx])

---

使用

a

将掩码应用于

数组

，然后对掩码数组求和。例如：

# Prepare sample array and indices
a = np.arange(10*10).reshape(10,10)
ind = [(1,0), (2, 4), (2,6), (7,7), (8,9), (9,3)]

# Cast list of coordinates into a form that will work for indexing
indx = np.split(np.array(ind), 2, axis = 1)

# A warning may be raised about not using tuples for indexing. You can use tuple(indx) to avoid that.
np.sum(a[indx])