PHP：日历、重复事件每X周一次

我正在尝试从给定日期开始每隔X天获取一个日历。我想我在某种程度上已经有了逻辑，但对于一小段日期，我得到了意想不到的结果

以下代码取自我的项目：

$start_time = 1345935600; //Sept 25th 2011; 
$end_time = 1355011200; //Dec 9th 2011;

$sStartDate = date("Y-m-d", $start_time) . " " . date("H:i:s", strtotime("00:00:00"));
$sEndDate = date("Y-m-d", $end_time) . " " . date("H:i:s", strtotime("00:00:00"));
$sCurrentDate = $sStartDate; 

while($sCurrentDate < $sEndDate)
{                                       
    $t_date = strtotime($sCurrentDate);
    $s_date = strtotime(date("Y-m-d", strtotime("08/30/2011")));

    $recurs_every = 60 * 60 * 24 * 2; //occurs every 2 days

    echo date("Y-m-d H:i:s", $t_date) . " " . date("Y-m-d H:i:s", $s_date) . " " . (($t_date - $s_date) % $recurs_every) . " " . $recurs_every . "<BR>" ;   

    $sCurrentDate = date("Y-m-d", strtotime("+1 day", strtotime($sCurrentDate)));                                               
}

最后几行是我的问题

3600是一个小时，我不知道这是从哪里来的。奇怪的是，快进到2012年3月26日，它又开始工作了，但同样的错误发生在2012年10月29日

这件事我已经做了几个小时了，还没弄明白。非常感谢您的帮助

---

谢谢

在一些国家，在夏季和冬季，时钟在3月27日和10月30日转换为1小时。因此有1小时的时差

->

例如：

<?

error_reporting(E_ALL);

$start_time = 1345935600; //Sept 25th 2011; 
$end_time = 1355011200; //Dec 9th 2011;

$sStartDate = date("Y-m-d", $start_time) . " " . date("H:i:s", strtotime("00:00:00"));
$sEndDate = date("Y-m-d", $end_time) . " " . date("H:i:s", strtotime("00:00:00"));
$sCurrentDate = $sStartDate; 

$lastDate = 0;
$corr = 0;

while($sCurrentDate < $sEndDate)
{                                       
    $t_date = strtotime($sCurrentDate);
    $s_date = strtotime(date("Y-m-d", strtotime("08/30/2011")));

    $recurs_every = 60 * 60 * 24 * 2; //occurs every 2 days

    echo date("Y-m-d H:i:s", $t_date) . " " . date("Y-m-d H:i:s", $s_date) . " " . (($t_date - $s_date + $corr) % $recurs_every) . " " . $recurs_every . "<BR>" ;   

    $lastDate = strtotime($sCurrentDate);
    $sCurrentDate = date("Y-m-d", strtotime("+1 day", strtotime($sCurrentDate)));             

    if(strtotime($sCurrentDate) - $lastDate != 60 * 60 * 24) {
        $corr -= strtotime($sCurrentDate) - $lastDate - 60 * 60 * 24;
    }
}

?>

---

我已经给了你回答这个问题和努力的答案。最后，我重新思考了一下，做了更多的谷歌搜索，这就是我想到的

$start_time = 1316905200;
$end_time = 1320537600;

$sStartDate = date("Y-m-d", $start_time);
$sEndDate = date("Y-m-d", $end_time);

$sStartDate = new DateTime($sStartDate);
$sEndDate = new DateTime($sEndDate);

$sCurrentDate = $sStartDate; 
$recurs_every = 60 * 60 * 24 * 2; //occurs every 2 days

while($sCurrentDate->format('U') < $sEndDate->format('U'))
{       
    $s_date = new DateTime("08/30/2011");

    echo $sCurrentDate->format('Y-m-d') . " " . $s_date->format('Y-m-d') . " " . ceil(($sCurrentDate->format('U') - $s_date->format('U') - (chkTransitions($sCurrentDate->format('U')) == 'GMT' ? 3600 : 0)) % $recurs_every) . "<BR>";

    $sCurrentDate->add(new DateInterval('P1D'));    
}

function chkTransitions($dt)
{
    $timezone = new DateTimeZone("Europe/London");
    $transitions = $timezone->getTransitions($dt, $dt);

    $offset = $transitions[0]['offset']; 
    $abbr = $transitions[0]['abbr']; 

    return $abbr;
}

---

我想这可能与此有关。我现在脑子乱糟糟的。你可以更新我的代码来解决这个问题吗？我编辑了我的帖子。应该是这样的。可能不是最好的解决方案，但在我的测试中应该是可行的。

$start_time = 1316905200;
$end_time = 1320537600;

$sStartDate = date("Y-m-d", $start_time);
$sEndDate = date("Y-m-d", $end_time);

$sStartDate = new DateTime($sStartDate);
$sEndDate = new DateTime($sEndDate);

$sCurrentDate = $sStartDate; 
$recurs_every = 60 * 60 * 24 * 2; //occurs every 2 days

while($sCurrentDate->format('U') < $sEndDate->format('U'))
{       
    $s_date = new DateTime("08/30/2011");

    echo $sCurrentDate->format('Y-m-d') . " " . $s_date->format('Y-m-d') . " " . ceil(($sCurrentDate->format('U') - $s_date->format('U') - (chkTransitions($sCurrentDate->format('U')) == 'GMT' ? 3600 : 0)) % $recurs_every) . "<BR>";

    $sCurrentDate->add(new DateInterval('P1D'));    
}

function chkTransitions($dt)
{
    $timezone = new DateTimeZone("Europe/London");
    $transitions = $timezone->getTransitions($dt, $dt);

    $offset = $transitions[0]['offset']; 
    $abbr = $transitions[0]['abbr']; 

    return $abbr;
}