Php 将查询数据传递给方法的正确方法?

Php 将查询数据传递给方法的正确方法?,php,Php,我有一个用户类,我想知道处理插入的“最推荐”方法是什么 选项1:使用现有对象 // insert a new user and return the user id public function insert() { $sql = "INSERT INTO users (username, password, email, avatar, subscribe, created, last_login, valid) VALUES

我有一个用户类,我想知道处理插入的“最推荐”方法是什么

选项1:使用现有对象

// insert a new user and return the user id
public function insert() {
    $sql = "INSERT INTO users (username, password, email, avatar, subscribe, created, last_login, valid) VALUES
                              (?, ?, ?, ?, ?, ?, ?, ?)";
    $sth = $this->db->prepare($sql);
    $sth->bindParam(1, $this->username, PDO::PARAM_STR);
    $sth->bindParam(2, $this->password, PDO::PARAM_STR);
    $sth->bindParam(3, $this->email, PDO::PARAM_STR);
    $sth->bindParam(4, $this->avatar, PDO::PARAM_STR);
    $sth->bindParam(5, $this->subscribe, PDO::PARAM_STR);
    $sth->bindParam(6, $this->created, PDO::PARAM_STR);
    $sth->bindParam(7, $this->last_login, PDO::PARAM_STR);
    $sth->bindParam(8, $this->valid, PDO::PARAM_STR);
    $sth->execute();

    return $this->db->lastInsertId();
}
选项2:将信息作为数组传入

// insert a new user and return the user id
public function insert(array $fields = array()) {
    if(!empty($fields)) {
        $sql = "INSERT INTO users (username, password, email, avatar, subscribe, created, last_login, valid) VALUES
                                  (:username, :password, :email, :avatar, :subscribe, :created, :last_login, :valid)";
        $sth = $this->db->prepare($sql);
        $sth->execute($fields);

        return $this->db->lastInsertId();
    }
}

另一种选择?这有什么区别吗?

两种方法都可以,但就我个人而言,我建议第二种选择

只是你为什么喜欢第二种选择的具体原因?