Php 将查询数据传递给方法的正确方法?
我有一个用户类,我想知道处理插入的“最推荐”方法是什么 选项1:使用现有对象Php 将查询数据传递给方法的正确方法?,php,Php,我有一个用户类,我想知道处理插入的“最推荐”方法是什么 选项1:使用现有对象 // insert a new user and return the user id public function insert() { $sql = "INSERT INTO users (username, password, email, avatar, subscribe, created, last_login, valid) VALUES
// insert a new user and return the user id
public function insert() {
$sql = "INSERT INTO users (username, password, email, avatar, subscribe, created, last_login, valid) VALUES
(?, ?, ?, ?, ?, ?, ?, ?)";
$sth = $this->db->prepare($sql);
$sth->bindParam(1, $this->username, PDO::PARAM_STR);
$sth->bindParam(2, $this->password, PDO::PARAM_STR);
$sth->bindParam(3, $this->email, PDO::PARAM_STR);
$sth->bindParam(4, $this->avatar, PDO::PARAM_STR);
$sth->bindParam(5, $this->subscribe, PDO::PARAM_STR);
$sth->bindParam(6, $this->created, PDO::PARAM_STR);
$sth->bindParam(7, $this->last_login, PDO::PARAM_STR);
$sth->bindParam(8, $this->valid, PDO::PARAM_STR);
$sth->execute();
return $this->db->lastInsertId();
}
选项2:将信息作为数组传入
// insert a new user and return the user id
public function insert(array $fields = array()) {
if(!empty($fields)) {
$sql = "INSERT INTO users (username, password, email, avatar, subscribe, created, last_login, valid) VALUES
(:username, :password, :email, :avatar, :subscribe, :created, :last_login, :valid)";
$sth = $this->db->prepare($sql);
$sth->execute($fields);
return $this->db->lastInsertId();
}
}
另一种选择?这有什么区别吗?两种方法都可以,但就我个人而言,我建议第二种选择只是你为什么喜欢第二种选择的具体原因?