Php 如何显示用户上传的视频
我有下面的代码,但我想编辑它,让它要求用户的标题和描述,然后他们上传文件,最后一旦他们提交,它出现在页面上的缩略图 我不是要求有人为我做这件事,只是为了引导我走上正确的方向 守则:Php 如何显示用户上传的视频,php,mysql,Php,Mysql,我有下面的代码,但我想编辑它,让它要求用户的标题和描述,然后他们上传文件,最后一旦他们提交,它出现在页面上的缩略图 我不是要求有人为我做这件事,只是为了引导我走上正确的方向 守则: <? $allowedExts = array("jpg", "jpeg", "gif", "png", "mp3", "mp4", "wma"); $allowType = array("video/mp4","audio/mp3","audio/wma","image/png","image/gif","i
<?
$allowedExts = array("jpg", "jpeg", "gif", "png", "mp3", "mp4", "wma");
$allowType = array("video/mp4","audio/mp3","audio/wma","image/png","image/gif","image/jpeg");
$maxSize = 20000000000000;
$extension = pathinfo($_FILES['file']['name'], PATHINFO_EXTENSION);
$pathToUpload = 'upload/';
if (
in_array($_FILES["file"]["type"], $allowType) &&
in_array($extension, $allowedExts) &&
$_FILES["file"]["size"] <= $maxSize
) {
if ($_FILES["file"]["error"] > 0) {
echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
} else {
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";
if (file_exists($pathToUpload . $_FILES["file"]["name"])) {
echo $_FILES["file"]["name"] . " already exists. ";
} else {
move_uploaded_file($_FILES["file"]["tmp_name"], $pathToUpload . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
}
}
} else {
echo "Invalid file";
}
生成缩略图:
显示视频:
可能的重复不完全是重复,但我想您知道如何从PHP输出HTML。;)