PHP数组未正确迭代，仅获取第一个结果

这仍然很有趣，让我感到困惑。我有一个名为Workday的“order”对象数组，如果我打印该数组，我会得到以下结果：

Workday Object
(
    [workday] => Array
        (
            [0] => Order Object
                (
                    [id] => 3
                    [date] => 2013-08-02
                    [username] => userXYZ
                    [number] => 33333333 
                    [duration_start] => 20:51:00
                    [duration_end] => 21:51:00
                    [total] => $340.00
                )

            [1] => Order Object
                (
                    [id] => 3
                    [date] => 2013-08-03
                    [username] => userXXA
                    [number] => 87653212 
                    [duration_start] => 10:51:00
                    [duration_end] => 11:54:00
                    [total] => $20.00
                )

            [2] => Order Object
                (
                    [id] => 3
                    [date] => 2013-08-01
                    [username] => userXYD
                    [number] => 12345678 
                    [duration_start] => 08:37:00
                    [duration_end] => 10:01:00
                    [total] => $10.00
                )

        )

)

问题似乎是当我尝试迭代数组时，它只输出第一个结果。我错过了什么

$workday = new Workday();
$workday->Get($username, $duration_start, $duration_end);

$i = 0;
if($workday != null)
{
    foreach($workday as $orders)
    {
        echo "ID: " . $orders[$i]->number;
        $i++;
    }
}

---

您需要遍历对象的

workday

成员变量

if($workday != null)
{
    foreach($workday['workday'] as $orders)
    {
        echo "ID: " . $orders->number;
    }
}

试试这个

foreach($workday->workday as $orders)
    {
        echo "ID: " . $orders->number;
     }

---

您得到的错误告诉您发生了什么：您试图将对象用作数组。迭代

$workday->workday

（对象中的数组）

---

刚刚尝试，出现了致命错误：无法将Workday类型的对象用作数组是否确实不是只返回一个结果的

Get（）

方法？您是否将

$username、$duration\u start、$duration\u end

作为搜索参数传递，因为这可能是您只收到一个结果的原因。@DaveChen您的答案是正确的，为什么要删除它？答对了！非常感谢。那么，我的阵列设计是否糟糕，或者只是n00b开发人员的疏忽：P

foreach ($workday->workday as $orders) { ... }