在php中通过url传递数据时出现问题

在php中将数据从表单通过url传递到数据库时出现以下错误

<b>Notice</b>:  Trying to get property 'name' of non-object in 
<b>C:\xampp\htdocs\api\product\create.php</b> on line <b>24</b><br />
<b>Notice</b>:  Trying to get property 'price' of non-object in 
<b>C:\xampp\htdocs\api\product\create.php</b> on line <b>25</b><br />
<br />
<b>Notice</b>:  Trying to get property 'description' of non-object in 
<b>C:\xampp\htdocs\api\product\create.php</b> on line <b>26</b><br />
 <br />
<b>Notice</b>:  Trying to get property 'category_id' of non-object in 
<b>C:\xampp\htdocs\api\product\create.php</b> on line <b>27</b><br />
 {"message": "Product was created."}

注意：尝试获取中非对象的属性“name”
第24行的C:\xampp\htdocs\api\product\create.php

注意：试图在中获取非对象的属性“价格”
第25行的C:\xampp\htdocs\api\product\create.php



注意：正在尝试获取中非对象的属性“说明”
第26行的C:\xampp\htdocs\api\product\create.php



注意：正在尝试获取中非对象的属性“category\u id”
第27行的C:\xampp\htdocs\api\product\create.php

{“消息”：“产品已创建。”}

下面是create.php文件中的代码，在提交后将数据从表单传递到数据库时，我遇到了这个问题

create.php：

<?php
   // required headers
   header("Access-Control-Allow-Origin: *");
   header("Content-Type: application/json; charset=UTF-8");
   header("Access-Control-Allow-Methods: POST");
   header("Access-Control-Max-Age: 3600");
   header("Access-Control-Allow-Headers: Content-Type, Access-Control-Allow- 
   Headers, Authorization, X-Requested-With");

  // get database connection
   include_once '../config/database.php';

 // instantiate product object
  include_once '../objects/product.php';

  $database = new Database();
  $db = $database->getConnection();

 $product = new Product($db);

 // get posted data
  $data = json_decode(file_get_contents("php://input"));

  // set product property values
 $product->name = $data->name;
 $product->price = $data->price;
 $product->description = $data->description;
 $product->category_id = $data->category_id;
 $product->created = date('Y-m-d H:i:s');

 // create the product
 if($product->create()){
    echo '{';
       echo '"message": "Product was created."';
   echo '}';
  }

// if unable to create the product, tell the user
 else{
   echo '{';
       echo '"message": "Unable to create product."';
  echo '}';
  }

   ?>

---

请通过使用php将数据从表单通过url传递到数据库来帮助解决此问题

可能的重复说明

$data

不是对象。你为什么相信

php://input“

是否包含JSON字符串？设置后，您是否尝试过检查

$data

是什么？