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Php 如何使用for-each语句在单独的for-each语句中执行两个MySQLi查询?_Php_Mysqli - Fatal编程技术网

Php 如何使用for-each语句在单独的for-each语句中执行两个MySQLi查询?

Php 如何使用for-each语句在单独的for-each语句中执行两个MySQLi查询?,php,mysqli,Php,Mysqli,我试图在二次查询中使用MySQLi结果中的一行。 但是我得到了一些意想不到的结果 <?php $mysqli = new mysqli('connection'); if ($mysqli->connect_error) {die('Connect Error: ' . $mysqli->connect_error);} $today = date("Ymd"); $query = "SELECT course FROM dailytips WHERE date = 2

我试图在二次查询中使用MySQLi结果中的一行。 但是我得到了一些意想不到的结果

<?php 

$mysqli = new mysqli('connection');
if ($mysqli->connect_error) {die('Connect Error: ' . $mysqli->connect_error);}

$today = date("Ymd");

$query = "SELECT course FROM dailytips WHERE date = 20130724 GROUP BY course"; 
$result = $mysqli->query($query);
while($row = $result->fetch_array()) 
{
    $rows[] = $row; } 
    foreach($rows as $row) 
    { 
        echo $row['course'] . "<br/>"; 
        $query2 = "SELECT horse, time, date FROM dailytips WHERE date = 20130724 and course ='{$row['course']}' ORDER BY time"; 
        $result2 = $mysqli->query($query2);

        $today_uk = " " . date("d/m/y");
        while($row2 = $result2->fetch_array()) 
        {
            $rows2[] = $row2;
        }
        foreach($rows2 as $row2)
        {
           $date = $row2['date'];
           $date = date("d/m/y", strtotime($date));

           echo '<div style= "width:600px; font-family:verdana;"><div style="float:left; width:400px; margin-bottom:10px; margin-top10px;">'.$row2['time'] . "-" . $row2['horse'] .' </div>' ;                         
        }
    }

$result->close();
$mysqli->close(); 

?>
而我想要

ipswich
11:00-running
12:00-flamingo rider
14:00-lightning 

norwich
13:10-ed is back
14:05-redrum
17:05-pickle
被退回

如何在第二秒内释放每个查询的结果?

天哪,真是一团糟。 试试这个

<?php 

$mysqli = new mysqli('connection');
if ($mysqli->connect_error) {die('Connect Error: ' . $mysqli->connect_error);}

$today = date("Ymd");

$query = "SELECT course FROM dailytips WHERE date = 20130724 GROUP BY course"; 
$result = $mysqli->query($query);

$row = $result->fetch_array();

echo $row['course'] . "<br/>"; 
do {

    $query2 = "SELECT horse, time, date FROM dailytips WHERE date = 20130724 and course ='{$row['course']}' ORDER BY time"; 
    $result2 = $mysqli->query($query2);

    $today_uk = " " . date("d/m/y");

    while($row2 = $result2->fetch_array()) 
    { 
        $date = $row2['date'];
        $date = date("d/m/y", strtotime($date));

        echo '<div style= "width:600px;font-family:verdana;"><div style="float:left; width:400px; margin-bottom:10px; margin-top:10px;">'.$row2['time'] . "-" . $row2['horse'] .' </div>' ;                         
    } 

  } while ( $row = $result->fetch_array() );

   $result->close();
   $result2->close();
   $mysqli->close(); 
?>


请努力缩进您的代码。。。这还不确定,我能做到。是否有关于如何缩进的参考?我自学成才,从不太确定@EdWright有两种主要风格:等等,我不太确定。你确定你可以用这种方式跨越2个记录集吗?试试看,这给了我一个空白页:-/@EdWright在
中使用的
date
列的数据类型是什么,其中date=9999999
@EdWright好的,当我将select更改为使用
$today=date(“Ymd”)生成的日期时,我可能假设了很多。我猜数据库中没有所有日期的数据,因此我将代码更改回select语句中的硬编码
date=20130724
。现在再试一次。我还修复了css“margin-top10px;”中的一个bug更改为“页边距顶部:10px`
<?php 

$mysqli = new mysqli('connection');
if ($mysqli->connect_error) {die('Connect Error: ' . $mysqli->connect_error);}

$today = date("Ymd");

$query = "SELECT course FROM dailytips WHERE date = 20130724 GROUP BY course"; 
$result = $mysqli->query($query);

$row = $result->fetch_array();

echo $row['course'] . "<br/>"; 
do {

    $query2 = "SELECT horse, time, date FROM dailytips WHERE date = 20130724 and course ='{$row['course']}' ORDER BY time"; 
    $result2 = $mysqli->query($query2);

    $today_uk = " " . date("d/m/y");

    while($row2 = $result2->fetch_array()) 
    { 
        $date = $row2['date'];
        $date = date("d/m/y", strtotime($date));

        echo '<div style= "width:600px;font-family:verdana;"><div style="float:left; width:400px; margin-bottom:10px; margin-top:10px;">'.$row2['time'] . "-" . $row2['horse'] .' </div>' ;                         
    } 

  } while ( $row = $result->fetch_array() );

   $result->close();
   $result2->close();
   $mysqli->close(); 
?>