Php 正则表达式以匹配前面带有点的数字
我有一个字符串：Php 正则表达式以匹配前面带有点的数字,php,regex,preg-replace,preg-match,Php,Regex,Preg Replace,Preg Match,我有一个字符串： Product, Q.ty: 1, Price: 120.00 我想选择第一个逗号后直到最后两个十进制数字（.00）的所有内容，或者，换句话说，选择产品，尽管它是可变的；不可变的是，Q.t，而且众所周知，字符串中的最后两个字符将是两个数字，前面是一个点——但是只有最后一个字符将始终是0，它前面的字符可以是任何0-9，但始终是一个数字 我用这个来匹配字符串： preg_replace('/' . preg_quote(', Q.t') . '.*?' . preg_quote(
Product, Q.ty: 1, Price: 120.00
产品，Q.t00-9preg_replace('/' . preg_quote(', Q.t') . '.*?' . preg_quote('.00') . '/', '', $data );
/(\d+\.\d{2})$/
/(\d+\.\d{2})$/
哪一个将捕获任何带小数点的尾随“数字”？如果需要文字点，应将其替换为：\。如果需要文字点，应将其替换为：\
/([^,]*), Q\.ty: (\d*), Price: (\d*\.\d{2})/
（[^，]*）， Product, Q.ty: 1, Price: 120.00
$1 = Product
$2 = 1
$3 = 120.00
（[^，]*）， Product, Q.ty: 1, Price: 120.00
$1 = Product
$2 = 1
$3 = 120.00
(.+?), (Q\.ty: \d+, .+?\.\d{2})
(.+?), (Q\.ty: \d+, .+?\.\d{2})
<?php
$string = "Product, Q.ty: 1, Price: 120.00";
$removals = array(",",":");
$stime = microtime();
$nstring = str_replace($removals,'',$string);
$parts = explode(" ",$nstring);
echo microtime()-$stime."secs\n";
print_r($parts);
$pattern = "!^([A-Za-z]+),\s([A-Za-z.]+)\:\s([0-9]+),\s([A-Za-z]+):\s([0-9.]+)$!";
$ptime = microtime();
$m = preg_match($pattern,$string,$matches);
echo microtime()-$ptime."secs\n";
print_r($matches);
?>
$string$pattern = "!^(Product), (Q\.ty): ([0-9]+), (Price): ([0-9.]+)$!";
<?php
$string = "Product, Q.ty: 1, Price: 120.00";
$removals = array(",",":");
$stime = microtime();
$nstring = str_replace($removals,'',$string);
$parts = explode(" ",$nstring);
echo microtime()-$stime."secs\n";
print_r($parts);
$pattern = "!^([A-Za-z]+),\s([A-Za-z.]+)\:\s([0-9]+),\s([A-Za-z]+):\s([0-9.]+)$!";
$ptime = microtime();
$m = preg_match($pattern,$string,$matches);
echo microtime()-$ptime."secs\n";
print_r($matches);
?>
$string$pattern = "!^(Product), (Q\.ty): ([0-9]+), (Price): ([0-9.]+)$!";
作为一个小小的提示，您可以在正则表达式中使用
dd