Php 一个数据库工作，另一个不工作

我有一个数据库，其中有4个表，2个用于私人用户，2个用于业务用户。出于某种原因，当我尝试使用商业用户的电子邮件登录时，它不起作用，但用户名起作用，在私有表中，它起作用，这是我的代码，如果我没有正确解释，请告诉我，我会尽力再解释一遍

    $password = $_POST['password'];
    $emailuser = $_POST['unameemail'];
    $password = mysqli_real_escape_string($sql , $password); 
    $emailuser = mysqli_real_escape_string($sql , $emailuser); 
    $pwcheck = "
    SELECT * FROM private AS p 
    INNER JOIN user_private_data 
    AS c ON p.id = c.id 
    WHERE username='$emailuser' OR email='$emailuser'"; // part that works fine 
    $resultcheck = mysqli_query($sql , $pwcheck); // part that works fine 
    $rowcheck = mysqli_fetch_array($resultcheck , MYSQLI_ASSOC); // part that works fine 
    $hash = $rowcheck['password']; // part that works fine 
    $hash_pwd = password_verify($password , $hash);
    if ($hash_pwd != 0) {
        $_SESSION['username'] = $rowcheck['username']; // part that works fine  
        $_SESSION['logged'] = true; // part that works fine 
        header("refresh:0;url=../blablabla.php");     // part that works fine                   
    } else {
        $privateuser = "
        SELECT * FROM business AS d 
        INNER JOIN user_business_data 
        AS j ON d.id = j.id 
        WHERE username='$emailuser' OR email='$emailuser'"; // doesn't work
        $resultprivate = mysqli_query($sql , $privateuser); // doesn't work
            $rowprivate = mysqli_fetch_array($resultprivate , MYSQLI_ASSOC);
        $hashprivate = $rowprivate['password'];
        $hash_private = password_verify($password , $hashprivate);
        if ($hash_private != 0) {

            $_SESSION['username'] = $rowprivate['username'];
            $_SESSION['logged'] = true;
            $_SESSION['business'] = $rowprivate['bname'];
            $_SESSION['type'] = 'business';
} 

---

试试这个：在获取之前，您需要检查查询是否确实有结果 我假设变量$sql是在您的连接中定义的

<?php

$password = $_POST['password'];
$emailuser = $_POST['unameemail'];
$password = mysqli_real_escape_string($sql, $password);
$emailuser = mysqli_real_escape_string($sql, $emailuser);
$pwcheck = "
            SELECT * FROM private AS p 
            INNER JOIN user_private_data 
            AS c ON p.id = c.id 
            WHERE username='$emailuser' OR email='$emailuser'"; // part that works fine 
$resultcheck = mysqli_query($sql, $pwcheck); // part that works fine 
$rowcheck = mysqli_fetch_array($resultcheck, MYSQLI_ASSOC); // part that works fine 
$hash = $rowcheck['password']; // part that works fine 
$hash_pwd = password_verify($password, $hash);
if ($hash_pwd != 0) {
    $_SESSION['username'] = $rowcheck['username']; // part that works fine  
    $_SESSION['logged'] = true; // part that works fine 
    header("refresh:0;url=../blablabla.php");     // part that works fine                   
} else {
    $privateuser = "
                SELECT * FROM business AS d 
                INNER JOIN user_business_data 
                AS j ON d.id = j.id 
                WHERE username='$emailuser' OR email='$emailuser'"; // doesn't work
    $resultprivate = mysqli_query($sql, $privateuser); // doesn't work
    if ($resultprivate->num_rows > 0) {
        $rowprivate = mysqli_fetch_array($resultprivate, MYSQLI_ASSOC);
        $hashprivate = $rowprivate['password'];
        $hash_private = password_verify($password, $hashprivate);
        if ($hash_private != 0) {

            $_SESSION['username'] = $rowprivate['username'];
            $_SESSION['logged'] = true;
            $_SESSION['business'] = $rowprivate['bname'];
            $_SESSION['type'] = 'business';
        } else {
            //no record
        }
    }
?>

在解析查询之前，请清理输入值。此脚本很容易受到SQL注入的攻击。您的脚本有可能发生错误。请查看发生了什么情况，即使使用此脚本也是登录页面，而不是注册页面“不工作”是不够的。当您访问业务用户的mysqli_查询时，您会遇到什么错误？我猜最后丢失的

}

只是一个复制/粘贴错误？