Php 合并2个数组并将其编码为Json将返回无效字符

我合并2个数组，以便将其编码为Json，但实际情况如下：

{"\u0000*\u0000_id":1,"\u0000*\u0000_mapper":{},"\u0000*\u0000_avatar":"","\u0000*\u0000_name":"Name","\u0000*\u0000_surname":"Name","\u0000*\u0000_email":"something@domain.com","\u0000*\u0000_gsm":"301313","\u0000*\u0000_password":"somepassword201","\u0000*\u0000_language":1,"\u0000*\u0000_phone":"","\u0000*\u0000_company":"","\u0000*\u0000_vat":"","\u0000*\u0000_registrationDate":"2015-07-07 09:55:31","\u0000*\u0000_address":8,"\u0000*\u0000_lastLogin":"2015-07-24 09:06:45","\u0000*\u0000_username":"someusername","\u0000*\u0000_salt":"12qidjoasidj8192u319ehj129dusafioj","\u0000*\u0000_hash":"","\u0000*\u0000_activated":true,"\u0000*\u0000_timeZone":0,"error":"false"}`

当我使用

json\u encode（）

代码：

---

如何解决此问题？

它与合并无关。显然，您的

$user

对象包含受保护的属性，这些属性在被强制转换到数组时会出现。这两个

NUL

字节以JSON格式编码为

\u0000

。

我这样做修复了它：

public function getuserAction() {
    if ($this->checkLoggedIn()) {
        $user = $this->cache->user;
        $info = array('error' => 'false');
        $response = $this->mergeJsons(Zend_Json::encode($info), Zend_Json::encode($user);
        $this->view->jsonResponse = $response;
        $this->renderScript('/appapi/showjson.phtml');
    }
}
//The 'true' parameter means it's gonna create an array from the Json
private function mergeJsons($json1, $json2) {
    $result = array_merge(Zend_Json::decode($json1, true), Zend_Json::decode($json2, true));

    return Zend_Json::encode($result);
}

---

请发布

var\u dump（$user）

的输出。这就是Unicode字符串在JSON中的编码方式。显然，

$user

具有Unicode属性名。

public function getuserAction() {
    if ($this->checkLoggedIn()) {
        $user = $this->cache->user;
        $info = array('error' => 'false');
        $response = $this->mergeJsons(Zend_Json::encode($info), Zend_Json::encode($user);
        $this->view->jsonResponse = $response;
        $this->renderScript('/appapi/showjson.phtml');
    }
}
//The 'true' parameter means it's gonna create an array from the Json
private function mergeJsons($json1, $json2) {
    $result = array_merge(Zend_Json::decode($json1, true), Zend_Json::decode($json2, true));

    return Zend_Json::encode($result);
}