如何在PHP中解码JSON字符串？

我有一个JSON字符串，如下所示：

{"addresses":{"address":[{"@array":"true","@id":"888888","@uri":"xyz","household":{"@id":"44444","@uri":"xyz"},"person":{"@id":"","@uri":""},"addressType":{"@id":"1","@uri":"xyz","name":"Primary"},"address1":"xyz","address2":null,"address3":null,"city":"xyz","postalCode":"111111"}]}}

什么是PHP来解码它并将

address1

、

address2

、

address3

、

city

和

postalCode

放入会话变量

到目前为止，我试过这个，但不起作用：

$results = json_decode(strstr($address, '{"addresses":{"address":[{'), true);
$_SESSION['address1'] = $results['address']['address1'];

---

谢谢

可以尝试$results['address']['address']['address1']

---

不知道为什么要使用strstr。但是在这个例子中，它看起来不会改变任何东西。

您可以使用print\r输出$results，以准确了解对象输出的外观。

print\r

是您了解JSON结构的朋友

<?php

$addresses = json_decode('{"addresses":{"address":[{"@array":"true","@id":"888888","@uri":"xyz","household":{"@id":"44444","@uri":"xyz"},"person":{"@id":"","@uri":""},"addressType":{"@id":"1","@uri":"xyz","name":"Primary"},"address1":"xyz","address2":null,"address3":null,"city":"xyz","postalCode":"111111"}]}}');

$_SESSION['address1'] = $addresses->addresses->address[0]->address1;
$_SESSION['address2'] = $addresses->addresses->address[0]->address2;
$_SESSION['address3'] = $addresses->addresses->address[0]->address3;
$_SESSION['city'] = $addresses->addresses->address[0]->city;
$_SESSION['postalCode'] = $addresses->addresses->address[0]->postalCode;

print_r($_SESSION);

---

如果您打印了阵列，您可以看到布局是如何的：

stdClass Object
(
  [addresses] => stdClass Object
    (
      [address] => Array
        (
          [0] => stdClass Object
            (
              [@array] => true
              [@id] => 888888
              [@uri] => xyz
              [household] => stdClass Object
                (
                  [@id] => 44444
                  [@uri] => xyz
                )

              [person] => stdClass Object
                (
                  [@id] => 
                  [@uri] => 
                )

              [addressType] => stdClass Object
                (
                  [@id] => 1
                  [@uri] => xyz
                  [name] => Primary
                )

              [address1] => xyz
              [address2] => 
              [address3] => 
              [city] => xyz
              [postalCode] => 111111
            )
        )
    )
)

---

为什么不解码整个JSON字符串，然后得到您需要的呢

$address = '{"addresses":{"address":[{"@array":"true","@id":"888888","@uri":"xyz","household":{"@id":"44444","@uri":"xyz"},"person":{"@id":"","@uri":""},"addressType":{"@id":"1","@uri":"xyz","name":"Primary"},"address1":"xyz","address2":null,"address3":null,"city":"xyz","postalCode":"111111"}]}}';
$results = json_decode($address, true);
$address = $results['addresses']['address'][0];
print $address['address1'];
print $address['address2'];
print $address['postalCode'];

将json格式的字符串解码为PHP对象

试试这个：

$results = json_decode($address);
$results['address1'] = $results->addresses->address[0]->address1;
$results['address2'] = $results->addresses->address[0]->address2;
$results['address3'] = $results->addresses->address[0]->address3;
$results['city'] = $results->addresses->address[0]->city;
$results['postalCode'] = $results->addresses->address[0]->postalCode;

编辑-更新，我一开始误读了你的JSON。

JSON\u decode（$jsonData）返回一个对象，而不是数组

例如：

stdClass Object
(
    [addresses] => stdClass Object
        (
            [address] => Array
                (
                    [0] => stdClass Object
                        (
                            [@array] => true
                            [@id] => 888888
                            [@uri] => xyz
                            [household] => stdClass Object
                                (
                                    [@id] => 44444
                                    [@uri] => xyz
                                )

                            [person] => stdClass Object
                                (
                                    [@id] => 
                                    [@uri] => 
                                )

                            [addressType] => stdClass Object
                                (
                                    [@id] => 1
                                    [@uri] => xyz
                                    [name] => Primary
                                )

                            [address1] => xyz
                            [address2] => 
                            [address3] => 
                            [city] => xyz
                            [postalCode] => 111111
                        )

                )

        )

)

访问数据的方式：

$object = json_decode($jsonString);
$object->addresses->address[0]; // First address object
$object->addresses->address[0]->{"@array"}; // Not good way to access object property (damn @)
$object->addresses->address[0]->address1;
$object->addresses->address[0]->addressType->{"@id"}; // Again damn @

请注意，这些“@array”和“@id”字段是无效的JSON符号，从技术上讲，它们会导致JSON解析器中出现未指定的行为。

此字段将把所有标量值和空值放入会话中，其中键不以@

$jsonString = '{"addresses":{"address":[{"@array":"true","@id":"888888","@uri":"xyz","household":{"@id":"44444","@uri":"xyz"},"person":{"@id":"","@uri":""},"addressType":{"@id":"1","@uri":"xyz","name":"Primary"},"address1":"xyz","address2":null,"address3":null,"city":"xyz","postalCode":"111111"}]}}';

$result = json_decode($jsonString);

// will put *all* scalar and null values into session where key does not begin with a @
foreach($result->addresses->address[0] as $key=>$value) {
    if (substr($key, 0, 1) != '@'  && (is_scalar($value) || is_null($value)) ) {
        $_SESSION[$key] = $value;
    } 
}

print_r($_SESSION);

?>

---

什么事情没有发生，而你却想发生？始终描述您想要的行为和您得到的行为。在输出任何内容和引用$会话之前，您是否调用了

session\u start（）

。。。如此少的问题向上投票。许多答案通常意味着简单的问题，而不是好的问题。对某些人来说简单，但对其他人来说不好，因此是问题。+1要按照显示的方式打印结果，请在print_r（）后添加标记。这件事我花了很长时间才弄明白！令人惊叹的！！！！非常感谢，这次成功了。我选择提到我正在使用strstr，因为我在$addresses中包含了一些其他头信息，需要将其切掉。但这确实起到了作用，我非常感激！！！

$jsonString = '{"addresses":{"address":[{"@array":"true","@id":"888888","@uri":"xyz","household":{"@id":"44444","@uri":"xyz"},"person":{"@id":"","@uri":""},"addressType":{"@id":"1","@uri":"xyz","name":"Primary"},"address1":"xyz","address2":null,"address3":null,"city":"xyz","postalCode":"111111"}]}}';

$result = json_decode($jsonString);

// will put *all* scalar and null values into session where key does not begin with a @
foreach($result->addresses->address[0] as $key=>$value) {
    if (substr($key, 0, 1) != '@'  && (is_scalar($value) || is_null($value)) ) {
        $_SESSION[$key] = $value;
    } 
}

print_r($_SESSION);

?>