Php foreach中计算列的和

我有一张mysql表

服务费

id service_name service_charges 

我使用mysql查询，比如

select service_name service, service_charges,count(service_name)as unit 
from service charges group_by service

在我使用的php文件中

foreach(services as service){
echo $service['service'];
echo $service['service_charges'];
echo $service['unit'];
$service_charges_total = (($service['service_charges'])*($service['unit']));
echo $sevice_charges_total;
}

我得到的结果如下：

现在，我如何获得$service_charges_total（金额列）的总额，即我想要的总额为4200+1200+350=5750

---

谢谢。

您可以在php中使用以下函数进行操作

$total=0;
foreach(services as service)
{
   echo $service['service'];
   echo $service['service_charges'];
   echo $service['unit'];
   $service_charges_total = (($service['service_charges'])*($service['unit']));
   echo $sevice_charges_total;
   $total+=$sevice_charges_total;
}
echo $total;

---

我希望这对你有用

将金额值存储在数组中，然后使用数组_sum（）

---

$serviceTotalAmount+=$service\u charges\u total；

select service_name as service, 
       service_charges,
       count(service_name) as unit,
       (select sum(service_charges) from service) as total_amount
from service as charges 
group_by service, 
         service_charges

SELECT sum(Amount) from service_charges;

$service_charges_total = (($service['service_charges'])*($service['unit']));
$array[]=$service_charges_total;
$total_sum=array_sum($array);
echo $total_sum;