Php 警告：mysql_num_rows（）：提供的参数不是有效的mysql结果资源nationbuilder webhooks API

我们正在使用webhooks API为我们的nationbuilder帐户创建一个应用程序，我正在使用以下代码：

要连接并将表添加到数据库，我经常遇到以下错误：

警告：

mysql\u num\u rows（）

：第41行的/home/www/ran-methods.org/webhooks.php中提供的参数不是有效的mysql结果资源

下面是我的代码。非常感谢你

<?php 

// get the request
$data = $_REQUEST['payload'];
// sanitize the data
$unescaped_data = stripslashes($data);
 // set up our object
$person = json_decode($unescaped_data);

// assign variables
$id = $person->signup->nationbuilder_id; // used as a unique identifier
$first_name = $person->signup->first_name;
$last_name = $person->signup->last_name;
$mobile_phone = $person->signup->mobile_number;
$work_phone = $person->signup->work_phone_number;
$other_phone = $person->signup->phone_number;
$email_1 = $person->signup->email1;
$email_2 = $person->signup->email2;
$email_3 = $person->signup->email3;

// connect to our DB
$connect = mysql_connect("localhost","username redacted","password redacted");
mysql_select_db("emmtal_targets", $connect);

// let's create this table if it doesn't exist
$sqltable = "CREATE TABLE IF NOT EXISTS webhook_backup
(
    `first_name` varchar(80),
    `last_name` varchar(80),
    `nb_id` int,
    `mobile_phone` varchar(20),
    `work_phone` varchar(20),
    `other_phone` varchar(20),
    `email_1` varchar(255),
    `email_2` varchar(255),
    `email_3` varchar(255)
)";

// does this user exist in the DB already?
$query = "SELECT `nb_id` FROM `webhook_backup` WHERE `nb_id` = '". $id ."'";
$num_rows = mysql_num_rows($query);

// update if this user already exists
if ($num_rows > 0) {
    $update = "UPDATE `webhook_backup` SET
        `first_name` = '". $first_name ."'
        `last_name` = '". $last_name ."'
        `mobile_phone` = '". $mobile_phone. "'
        `work_phone` = '". $work_phone. "'
        `other_phone` = '". $other_phone. "'
        `email_1` = '". $email_1 ."'
        `email_2` = '". $email_2 ."'
        `email_3` = '". $email_3 ."'
        WHERE `nb_id` = '". $id ."'
        LIMIT 1";
    mysql_query($update, $connect);
}

// add a new row if this user does not yet exist
if ($num_rows == 0) {
    $insert = "INSERT INTO `webhook_backup`
        (`first_name`, `last_name`, `mobile_phone`, `work_phone`, `other_phone`,
        `email_1`, `email_2`, `email_3`, `nb_id`)
        VALUES ('". $first_name ."','". $last_name ."','". $mobile_phone ."','". $work_phone ."',
        '". $other_phone ."','". $email_1 ."','". $email_2 ."','". $email_3 ."','". $id ."')";
    mysql_query($insert, $connect);
}
?>

---

您需要运行查询…您正在尝试获取字符串的行数

 $query = mysql_query("SELECT `nb_id` FROM `webhook_backup` WHERE `nb_id` = '". $id ."'");
 $num_rows = mysql_num_rows($query);

但是，不要使用
mysql.*
函数，它们已被弃用。改为使用
mysqli.*
。
rtfm ok Now I在用mysqli替换所有mysql并替换这两行之后，我收到以下错误。警告：mysqli_select_db（）预期参数1为mysqli，第23行/home/www/ran-methods.org/webhooks.php中给出的字符串警告：mysqli_query（）预期至少有2个参数，第40行/home/www/ran-methods.org/webhooks.php中给出1警告：mysqli_num_rows（）期望参数1为mysqli_结果，第41行/home/www/ran-methods.org/webhooks.php中给出null警告：mysqli_query（）期望参数1为mysqli，第67I行/home/www/ran-methods.org/webhooks.php中给出的字符串我没有说“用‘mysqli_u’替换‘mysql_u’，它会神奇地工作。”我说“使用mysqli_u*”。阅读文档。