PHP到JSON到iPhone

可能重复：

我有一个输出以下JSON的php文件：

[{"0":"5","questionId":"5","1":"Morning Heart Rate","question":"Morning Heart Rate","2":"5","questionNumber":"5","3":"1","sectionId":"1"},{"0":"4","questionId":"4","1":"Evening Urine Colour","question":"Evening Urine Colour","2":"4","questionNumber":"4","3":"1","sectionId":"1"},{"0":"3","questionId":"3","1":"Evening Bodyweight","question":"Evening Bodyweight","2":"3","questionNumber":"3","3":"1","sectionId":"1"},{"0":"2","questionId":"2","1":"Morning Urine Colour","question":"Morning Urine Colour","2":"2","questionNumber":"2","3":"1","sectionId":"1"},{"0":"1","questionId":"1","1":"Morning Bodyweight","question":"Morning Bodyweight","2":"1","questionNumber":"1","3":"1","sectionId":"1"},{"0":"6","questionId":"6","1":"Time of Month (TOM)","question":"Time of Month (TOM)","2":"6","questionNumber":"6","3":"1","sectionId":"1"}]

这可以在以下链接中看到：

我使用JSONKit作为解码Objective C中JSON的框架。使用以下方法与php进行通信：

//方法

+(void)getQuestions:(NSString*)sectionId{
    NSString* url = @"http://dev.speechlink.co.uk/David/get_questions.php";
    NSURL *link = [NSURL URLWithString:url];
    ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:link]; 
    [request setPostValue:sectionId forKey:@"section"]; 
    [request setDelegate:self];
    [request setDidFinishSelector:@selector(requestFinished:)];
    [request startAsynchronous];    
}

- (void)requestFinished:(ASIHTTPRequest *)request
{
    //NSString *response = [request responseString];
    NSLog(@"hello"); //never prints
}

代表从未被呼叫过……有人能解释一下吗

- (void)getQuestions:(NSString*)sectionId 

将该方法声明为实例方法而不是类方法

设置

[request setDelegate:self]时

self必须是已分配的对象。

我检查了链接，它给出了您描述的响应。但是在您的代码中，您使用的链接与上面提供的链接不同

没有给出任何响应，这可能就是您的代表没有打电话的原因。请将“get_questions.php”更改为“get_questionstest.php”，它将正常工作

---

如果有任何问题，请告诉我。

我必须更改它们，因为我的实际php在返回数据之前需要一个POST变量-get_questionstest.php删除了_POST变量并使其独立运行…但我检查了此链接：它没有给出任何响应。您也可以在浏览器中签入。