Php 在多维数组中搜索并返回不带支持变量的结果
我有两个数组:Php 在多维数组中搜索并返回不带支持变量的结果,php,arrays,loops,multidimensional-array,Php,Arrays,Loops,Multidimensional Array,我有两个数组: $fruits = array( 'Apple' => array('id' => 1), 'Banana' => array('id' => 2), 'Peach' => array('id' => 3) ); $carts = array( 'Olivia' => array(51, 3, 2), 'Harry' => array(312, 314, 10), 'Charlie'
$fruits = array(
'Apple' => array('id' => 1),
'Banana' => array('id' => 2),
'Peach' => array('id' => 3)
);
$carts = array(
'Olivia' => array(51, 3, 2),
'Harry' => array(312, 314, 10),
'Charlie' => array(1, 314, 626)
);
我想写一些东西,如果一些水果id在购物车里。我有这个代码,它的工作
foreach ($carts as $cart) {
$boughtFruit = false;
foreach ($fruits as $fruit) {
if (in_array($fruit['id'], $cart)) {
echo "Fruit <br>";
$boughtFruit = true;
break;
}
}
if(!$boughtFruit){
echo "No Fruit <br>";
}
}
我不喜欢我的解决方案,因为我需要使用支持变量$boughtFruit
和2 foreach
您可以建议我使用
PHP
函数(如果存在)而不使用$boughtFruit
,使用相同的代码吗?您不需要内环,而是使用在数组中查找相同的值
$fru = array_column($fruits, "id");
foreach ($carts as $cart) {
echo count(array_intersect($cart, $fru)) ? "Fruit <br>" : "No Fruit <br>";
}
输出:
Fruit (Peach, Banana)
No Fruit
Fruit (Apple)
在中检查结果,您不需要使用内部循环,而是使用在数组中查找相同的值
$fru = array_column($fruits, "id");
foreach ($carts as $cart) {
echo count(array_intersect($cart, $fru)) ? "Fruit <br>" : "No Fruit <br>";
}
输出:
Fruit (Peach, Banana)
No Fruit
Fruit (Apple)
检查结果