搜索框无结果，PHP SQL
我试图使用if语句使搜索框正常工作，但由于某些原因，根本没有出现任何数据： 你能帮我纠正一下if语句，让它正常工作吗搜索框无结果，PHP SQL,php,mysql,sql,search,if-statement,Php,Mysql,Sql,Search,If Statement,我试图使用if语句使搜索框正常工作，但由于某些原因，根本没有出现任何数据： 你能帮我纠正一下if语句，让它正常工作吗 <?php if (isset($_POST['submit'])) { //capture search term and remove spaces at its both ends if the is any $searchTerm = trim($_GET['keyname']); echo '<html><head><ti
<?php
if (isset($_POST['submit'])) {
//capture search term and remove spaces at its both ends if the is any
$searchTerm = trim($_GET['keyname']);
echo '<html><head><title>View Records</title><link rel="stylesheet" href="assets/layouts/reset.css" type="text/css" /><link rel="stylesheet" href="assets/layouts/portal/style.css" type="text/css" /><link rel="stylesheet" href="http://portal.gtlaw.co.uk/assets/layouts/portal/icons.css?r=IanKnowles-RULZ" type="text/css" /><link rel="stylesheet" href="http://portal.gtlaw.co.uk/assets/javascript/jquery/themes/base/jquery.ui.all.css?MH=1"><link rel="stylesheet" href="http://portal.gtlaw.co.uk/assets/javascript/jquery/themes/plugins/ui.dropdownchecklist.standalone.css"><script src="http://portal.gtlaw.co.uk/assets/javascript/jquery/jquery-1.7.1.js?MH=1"></script><script src="http://portal.gtlaw.co.uk/assets/javascript/jquery/ui/jquery.ui.core.js?MH=1"></script><script src="http://portal.gtlaw.co.uk/assets/javascript/jquery/ui/jquery.ui.widget.js?MH=1"></script><script src="http://portal.gtlaw.co.uk/assets/javascript/jquery/ui/jquery.ui.datepicker.js?MH=1"></script><script src="http://portal.gtlaw.co.uk/assets/javascript/jquery/ui/i18n/jquery.ui.datepicker-en-GB.js?MH=1"></script><script src="http://portal.gtlaw.co.uk/assets/javascript/jquery/ui/jquery.ui.dropdownchecklist.js"></script><script src="http://portal.gtlaw.co.uk/assets/javascript/site/site.js"></script>';
//check whether the name parsed is empty
//database connection info
$host = "localhost"; //server
$db = "hidden"; //database name
$user = "hidden"; //dabases user name
$pwd = "hidden"; //password
//connecting to server and creating link to database
$link = mysqli_connect($host, $user, $pwd, $db);
//MYSQL search statement
$query = "SELECT * FROM usertracker WHERE firstname LIKE '%$searchTerm%' OR lastname LIKE '%$searchTerm%'";
$results = mysqli_query($link, $query);
/* check whethere there were matching records in the table
by counting the number of results returned */
if(mysqli_num_rows($results) >= 1)
{
$output = "";
while($row = mysqli_fetch_array($results))
{
$output .= '<tr class="heads">';
$output .= '<td>' . $row['id'] . '</td>';
$output .= "<td class=\"click\"><a href=\"viewtrackcase.php?id=" . $row['id'] . "\"><img src=\"assets/images/edit.png\" /> " . $row['firstname'] . " " . $row['lastname'] . "</a></td>";
$output .= '</tr>';
}
$output .= '</table>';
echo $output;
}
elseif($searchTerm == "")
{
echo "Enter name you are searching for.";
exit();
}
else
{
// connect to the database
include('connect-db.php');
// number of results to show per page
$per_page = 20;
// figure out the total pages in the database
$result = mysql_query("SELECT * FROM usertracker WHERE agent = '{$_SESSION['user']['username']}' ORDER BY `submitdate` ASC");
$total_results = mysql_num_rows($result);
$total_pages = ceil($total_results / $per_page);
// check if the 'page' variable is set in the URL (ex: view-paginated.php?page=1)
if (isset($_GET['page']) && is_numeric($_GET['page']))
{
$show_page = $_GET['page'];
// make sure the $show_page value is valid
if ($show_page > 0 && $show_page <= $total_pages)
{
$start = ($show_page -1) * $per_page;
$end = $start + $per_page;
}
else
{
// error - show first set of results
$start = 0;
$end = $per_page;
}
}
else
{
// if page isn't set, show first set of results
$start = 0;
$end = $per_page;
}
// display pagination
// display data in table
// loop through results of database query, displaying them in the table
for ($i = $start; $i < $end; $i++)
{
// make sure that PHP doesn't try to show results that don't exist
if ($i == $total_results) { break; }
// echo out the contents of each row into a table
echo '<tr class="heads">';
echo '<td>' . mysql_result($result, $i, 'id') . '</td>';
echo "<td class=\"click\"><a href=\"viewtrackcase.php?id=" . mysql_result($result, $i, 'id') . "\"><img src=\"assets/images/edit.png\" /> " . mysql_result($result, $i, 'firstname') . " " . mysql_result($result, $i, 'lastname') . "</a></td>";
echo "<td>" . mysql_result($result, $i, 'solicitor') . "</td>";
echo "<td>" . mysql_result($result, $i, 'status') . "</td>";
echo "<td>" . mysql_result($result, $i, 'agent') . "</td>";
echo "<td>" . mysql_result($result, $i, 'submitdate') . "</td>";
echo "</tr>";
}
// close table>
// pagination
echo "<p><b>View Page: </b> ";
for ($i = 1; $i <= $total_pages; $i++)
{
echo "<a href='viewtracker.php?page=$i'>$i</a> ";
}
echo " | Total records: $total_results";
echo "</p>";
}
}
?>
你能更具体地（通过编辑问题）你想做什么吗？我相信你有一个搜索页面，在那里你可以搜索和显示结果。当您选择一个结果时，它会显示属于该选择结果的记录？？为什么不将其分为两页，一页用于搜索和显示结果，另一页用于显示所选结果的详细信息以及属于该页面的记录。在第一页上始终显示搜索框，在第二页上从不创建搜索框。。。