Php 为什么最新Wordpress更新时出现未定义属性stdClass错误？

更新到最新的Wordpress core 5.2.3后，我在一个自定义插件文件中收到这些错误消息

Notice: Undefined property: stdClass::$addressLocality in 
/var/www/html/www.clientsite.com/wp/wp-content/plugins/hove- 
widgets/widgets/careers.php on line 52
Notice: Undefined property: stdClass::$addressRegion in 
/var/www/html/www.clientsite.com/wp/wp-content/plugins/hove- 
widgets/widgets/careers.php on line 53
Notice: Undefined property: stdClass::$addressLocality in 
/var/www/html/www.clientsite.com/wp/wp-content/plugins/hove- 
widgets/widgets/careers.php on line 52
Notice: Undefined property: stdClass::$addressRegion in 
/var/www/html/www.clientsite.com/wp/wp-content/plugins/hove- 
widgets/widgets/careers.php on line 53

我查看了文件，但我无法确定为什么它声称该财产未定义。错误消息来自以下文件：

<?php

function hove_get_careers(){
    $output = '';
    $response = file_get_contents('https://hire.withgoogle.com/v2/api/t/hovecom/public/jobs');
    $response = json_decode($response);
    usort($response,function($a,$b) {return strnatcasecmp($a->hiringOrganization->department->name,$b->hiringOrganization->department->name);});
    // /var_dump($response);die;
    $department=null;
    $count=0;
    foreach($response as $r){
        $title = $r->title;
        $url = $r->url;
        $addressLocality = !empty($r->jobLocation->address->addressLocality) ? $r->jobLocation->address->addressLocality : '';
        $addressRegion = !empty($r->jobLocation->address->addressRegion) ? $r->jobLocation->address->addressRegion : '';
        $location = $addressLocality.','.$addressRegion;
        $actualdepartment = $r->hiringOrganization->department->name;
        if($actualdepartment!=$department){
            $count++;
            if($count!=1){
                $output .= '</ul>'; 
            }
            $department=$actualdepartment;
            $output .= '<h3>'.$actualdepartment.'</h3>';
            $output .= '<ul class="careers">';
        }
        $output .= '<li class="press-job"><span class="details"><span class="title">'.$title.'</span><span class="location">'.$location.'</span></span><span class="cta">Learn More</span><a href="'.$url.'" class="ab-link"></a></li>';
    }
    $output .= '</ul>'; 
    return $output; 
}

---

问题在于，代码只检查
AddressLocation
和
addressRegion
是否为空。它不会检查它们是否实际可用。可能插件使用的API在某个时候发生了变化，并且说属性现在要么不再可用，要么只有在满足某些条件时才提供

要修复此通知，我们只需检查是否使用函数设置了这两个属性，如下所示：

$addressLocality = isset($r->jobLocation->address->addressLocality) && !empty($r->jobLocation->address->addressLocality) ? $r->jobLocation->address->addressLocality : '';
$addressRegion = isset($r->jobLocation->address->addressRegion) && !empty($r->jobLocation->address->addressRegion) ? $r->jobLocation->address->addressRegion : '';

以下内容超出了您问题的原始范围，但我想指出：如果
$AddressLocation
和
$addressRegion
为空，则
$location
将只是
，
，这可能不是理想的输出。我将添加此附加检查以确保
$location
为空或显示实际地址：

$location = ($addressLocality && $addressRegion) ? $addressLocality.','.$addressRegion : '';

代码中的第52行和第53行是什么？我猜是变量“<代码> $AddiSsListIs< /Calp>和<代码> $AddiSsReals<代码>，这是正确的吗？是的，这是正确的。请检查我的答案，如果它帮助考虑的话。如果您有任何问题，请毫不犹豫地提问。谢谢，但这似乎无法解决问题。服务器管理员已隐藏错误消息。我只能看到这页的格式有问题。我将尝试返回错误消息，以查看是否有任何更改。