Php 我如何才能将其导出最大连续+；价值

$variable

中有很多值，它们具有随机的-ve和+ve值。如何计算最大连续正值？比如说,

 $variable = array:12 [▼
              0 => 258300
              1 => 668000
              2 => -1510530
              3 => 15000
              4 => 2400
              5 => 13400
              6 => 284000
              7 => -45000000
              8 => 7209702
              9 => 1000074080
              10 => 0
              11 => 1100
            ]

在上述情况下，输出应如下所示：4具有正的最大构造性值。因为

              3 => 15000
              4 => 2400
              5 => 13400
              6 => 284000

这些值具有continue+ve值及其最大连续值。

• 创建一些变量来存储一些临时值
• 在

  $变量上循环，并确定它是否处于正趋势。正趋势意味着以前的值和当前值都是正的

• 将其存储在当前正向趋势中，并检查您以前的最大连续趋势是否被破坏。如果它被破坏，您可以将当前趋势设置为新的最大趋势

请尝试以下代码：

// Define a variable which stores the previous value
$prev = null;
$current_positive_trend = array();
$max_consecutive_positive_trends = array();

foreach ($variable as $value) {

    /* For PHP 5 you can do the following instead
    $prev = isset($prev) ? $prev : $value;
    */
    $prev = ($prev ?? $value); // first time consider current value

    // if current value and previous value is greater than zero
    if ($prev > 0 && $value > 0) {

        // add the value to current positive trend
        $current_positive_trend[] = $value;

        // check if the count of current positive trend array is more than
        // the max consecutive positive trends found till now
        if (count($current_positive_trend) > count($max_consecutive_positive_trends)) {

            // set current trend to max consecutive trends
            $max_consecutive_positive_trends = $current_positive_trend;
        }
    } else {

        // not in positive trend - reset
        $current_positive_trend = array();
    }
}

$max_times_consecutive_positive = count($max_consecutive_positive_trends);

// print the consecutive positive values (in max case
var_dump($max_consecutive_positive_trends);
// print the max times trend was positive.
echo $max_times_consecutive_positive;

• 创建一些变量来存储一些临时值
• 在

  $变量上循环，并确定它是否处于正趋势。正趋势意味着以前的值和当前值都是正的

• 将其存储在当前正向趋势中，并检查您以前的最大连续趋势是否被破坏。如果它被破坏，您可以将当前趋势设置为新的最大趋势

请尝试以下代码：

// Define a variable which stores the previous value
$prev = null;
$current_positive_trend = array();
$max_consecutive_positive_trends = array();

foreach ($variable as $value) {

    /* For PHP 5 you can do the following instead
    $prev = isset($prev) ? $prev : $value;
    */
    $prev = ($prev ?? $value); // first time consider current value

    // if current value and previous value is greater than zero
    if ($prev > 0 && $value > 0) {

        // add the value to current positive trend
        $current_positive_trend[] = $value;

        // check if the count of current positive trend array is more than
        // the max consecutive positive trends found till now
        if (count($current_positive_trend) > count($max_consecutive_positive_trends)) {

            // set current trend to max consecutive trends
            $max_consecutive_positive_trends = $current_positive_trend;
        }
    } else {

        // not in positive trend - reset
        $current_positive_trend = array();
    }
}

$max_times_consecutive_positive = count($max_consecutive_positive_trends);

// print the consecutive positive values (in max case
var_dump($max_consecutive_positive_trends);
// print the max times trend was positive.
echo $max_times_consecutive_positive;

---

你想用最少的代码完成吗

<?
$v = [
    258300,
    668000,
    -1510530,
    15000,
    2400,
    13400,
    284000,
    7209702,
    1000074080,
    0,
    1100,
    45,
    -1
];
$m=0;
$c=0;

foreach ($v as $i) {$c=($i>0)?((++$c>$m)?($m=$c):$c):0;};

var_dump($m);

---

您希望用最少的代码完成吗

<?
$v = [
    258300,
    668000,
    -1510530,
    15000,
    2400,
    13400,
    284000,
    7209702,
    1000074080,
    0,
    1100,
    45,
    -1
];
$m=0;
$c=0;

foreach ($v as $i) {$c=($i>0)?((++$c>$m)?($m=$c):$c):0;};

var_dump($m);

这是代码。您应该优化代码。我添加了一些注释，可以帮助您进行其他更改

你可以检查你想要的

这是代码。您应该优化代码。我添加了一些注释，可以帮助您进行其他更改

你可以检查你想要的

到目前为止您尝试了什么？到目前为止您尝试了什么？