Php mysql按dayname排序

我如何按日期名称订购mysql，即：星期日、星期一、星期二、星期三等等

SELECT 
    DAYNAME(dl.bookingDate) AS dayName, COUNT(dg.idDiary) AS totalBooked
FROM
    diary_list dl, diary_group dg
WHERE
    dl.idDiary = dg.idDiary AND dg.idService != 0 AND dl.status = 3
GROUP BY 
    dayName
ORDER BY 
    dayName ???

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您需要将函数

DAYOFWEEK

添加到您的

分组依据

和

订单依据

：

GROUP BY DAYOFWEEK(dl.bookingDate)
ORDER BY DAYOFWEEK(dl.bookingDate)

您可能还希望研究使用显式ANSI标准

JOIN

语法

SELECT 
    DAYNAME(dl.bookingDate) AS dayName, COUNT(dg.idDiary) AS totalBooked
FROM
    diary_list dl
JOIN diary_group dg
    ON dl.idDiary = dg.idDiary
WHERE
    dg.idService != 0 AND dl.status = 3
GROUP BY 
    DAYOFWEEK(dl.bookingDate)
ORDER BY 
    DAYOFWEEK(dl.bookingDate)

---

您可以制定自己的订单标准：

ORDER BY FIELD(DAY , '3', '4', '5', '6', '7','1', '2')

就你而言：

ORDER BY FIELD(DAY , '7','1', '2', '3', '4', '5', '6')

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阅读此内容了解更多信息

应按DAYNAME排序（dl.bookingDate）否，DAYNAME返回字符串值，星期六将在星期日之前排序。改为使用DAYOFWEEK，它为Su返回1，为Mo返回2，等等。请查看您保存的“我的一天”手册中的工作日（）。我的英雄。。谢谢：）