CakePHP:hasOne关系为字段返回null
我有两种型号,CakePHP:hasOne关系为字段返回null,php,cakephp,has-one,Php,Cakephp,Has One,我有两种型号,场馆和联系人,其中一个场馆有一个联系人,但一个联系人可以负责多个场馆。在我的表格中,vention.contactid引用列contact.id 我的模型是这样的: class Contact extends AppModel { public $useTable = 'contact'; public $belongsTo = [ 'Contact'=>[ 'className'=>'Venue',
场馆
和联系人
,其中一个场馆有一个联系人,但一个联系人可以负责多个场馆。在我的表格中,vention.contactid
引用列contact.id
我的模型是这样的:
class Contact extends AppModel {
public $useTable = 'contact';
public $belongsTo = [
'Contact'=>[
'className'=>'Venue',
'foreignKey'=>'contactid',
'conditions'=>['Contact.id = Venue.contactid']
]];
}
class Venue extends AppModel {
public $useTable = "venue";
public $hasOne = [
'Contact'=>[
'className'=>'Contact',
'foreignKey'=>'id',
'conditions'=>['Venue.contactid = Contact.id']
]];
}
问题是,当我检索场地时,
联系人
字段的所有内容都设置为null
您应该这样更改代码
class Contact extends AppModel {
public $useTable = 'contact';
public $belongsTo = [
'Venue'=>[
'className'=>'Venue',
'foreignKey'=>'contactid',
'conditions'=>['Venue.contactid = Contact.id' ]
]];
}
您的代码应该是:
class Contact extends AppModel {
public $useTable = 'contact';
public $hasMany = [ // Has many, you said it
'Venue'=> [ // Venue here, not Contact
'className'=>'Venue',
'foreignKey'=>'contactid'
] // No need of conditions, you don't have anything special
];
}
class Venue extends AppModel {
public $useTable = "venue";
public $belongsTo = [ // the contactid is in the venue table, it's a belongsTo not a hasOne
'Contact' => [
'className'=>'Contact',
'foreignKey'=>'contactid'
]
];
}
您在hasOne
和belongsTo
以及其他关系之间犯了一些错误,请查看此处
无论如何,您应该尽量保持CakePHP约定以简化代码。如果您将字段contactid
更改为contact\u id
,并在表名中添加s
,则您的代码将变为:
class Contact extends AppModel {
public $hasMany = ['Venue'] ;
}
class Venue extends AppModel {
public $belongsTo = ['Contact'] ;
}
我做了更改,但没有解决问题。你是否与$hasMany联系过?谢谢你,我回去工作后会试试这些。我是CakePHP新手,从以前的开发人员那里继承了数据库。