Php 按日期查看的最佳方法

我正在尝试为我的网站制作一个视图系统

我的MySQL数据库中有770行文章，我正在尝试做一个视图系统，以了解哪篇文章获得了最多的视图，以及什么时候获得了最多的视图。（今天，3天前，本周，本月）

我尝试在MySQL数据库中执行以下操作：

表：视图

ID  articleID   date

---

但我不知道如何总结？如果我要添加“视图”列，这对我没有帮助，因为我必须随时更改日期。

这是任何视图的代码

CREATE VIEW purpose AS
SELECT 
    articleID, 
    COUNT(articleID) as view_count 
FROM views 
WHERE date_condition_depending_on_purpose 
GROUP BY articleID

---

p.S.关于articleID的索引非常重要。

这是任何视图的代码

CREATE VIEW purpose AS
SELECT 
    articleID, 
    COUNT(articleID) as view_count 
FROM views 
WHERE date_condition_depending_on_purpose 
GROUP BY articleID

p.S.文章ID索引至关重要。

所有文章：

SELECT
    COUNT(*) AS number,
    articleID
FROM
    views
GROUP BY
    articleID
ORDER BY
    number DESC

仅2012年：

SELECT
    COUNT(*) AS number,
    articleID
FROM
    views
WHERE
    YEAR(date) = 2012
GROUP BY
    articleID
ORDER BY
    number DESC

对于每个月的特定文章：

SELECT
    COUNT(*) AS number,
    MONTH(date) AS stats_month,
    YEAR(date) AS stats_year
FROM
    views
GROUP BY
    stats_month,
    stats_year
ORDER BY
    number DESC

所有条款：

SELECT
    COUNT(*) AS number,
    articleID
FROM
    views
GROUP BY
    articleID
ORDER BY
    number DESC

仅2012年：

SELECT
    COUNT(*) AS number,
    articleID
FROM
    views
WHERE
    YEAR(date) = 2012
GROUP BY
    articleID
ORDER BY
    number DESC

对于每个月的特定文章：

SELECT
    COUNT(*) AS number,
    MONTH(date) AS stats_month,
    YEAR(date) AS stats_year
FROM
    views
GROUP BY
    stats_month,
    stats_year
ORDER BY
    number DESC

您在哪里存储“视图”？您在哪里存储“视图”？