Warning: file_get_contents(/data/phpspider/zhask/data//catemap/1/php/236.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Php 如何从数组创建唯一数组_Php_Arrays_Array Unique - Fatal编程技术网

Php 如何从数组创建唯一数组

Php 如何从数组创建唯一数组,php,arrays,array-unique,Php,Arrays,Array Unique,排列 我想从此数组创建新数组 如下所示,它应该给我“12”公共值,并添加其他值 排列 一个简单的foreach循环就可以做到这一点 [0] => Array ( [a1] => 12 [v1] => 4300.00 [v2] => 258.00 [v3] => 258.00 ) 请查找以下代码: $result = array(); foreach($yourArray as $arr

排列

我想从此数组创建新数组 如下所示,它应该给我“12”公共值,并添加其他值

排列


一个简单的foreach循环就可以做到这一点

[0] => Array
    (
        [a1] => 12
        [v1] => 4300.00
        [v2] => 258.00
        [v3] => 258.00
    )

请查找以下代码:

$result = array();
foreach($yourArray as $arr){
    foreach($arr as $i=>$v) {
        if(!isset($result[$i])) {
            $result[$i] = 0;
        }
        if($i == 'a1'){ 
            $result[$i] = $v;
        } else {
            $result[$i] += $v;
        }
    }
}

您的真正需求有点不清楚,因此此解决方案只是少数几种可能的解决方案之一

此脚本
a1
元素用作键,因此它将使用多个
a1

例如:

<?php
$a = [
    [
        'a1' => 12,
        'v1' => 3100.00,
        'v2' => 186.00,
        'v3' => 186.00,
    ],
    [
        'a1' => 12,
        'v1' => 1200.00,
        'v2' => 72.00,
        'v3' => 72.00,
    ],
    [
        'a1' => 13,
        'v1' => 2100.00,
        'v2' => 386.00,
        'v3' => 386.00,
    ],
    [
        'a1' => 13,
        'v1' => 1200.00,
        'v2' => 72.00,
        'v3' => 72.00,
    ]
];

$r = [];
foreach ($a as $item) {
    $key = $item['a1'];
    if (empty($r[$key]))
        $r[$key] = $item;
    else {
        foreach ($item as $k => $v) {
            if ($k !== 'a1')
                $r[$key][$k] = empty($r[$key][$k]) ? $item[$k] : $r[$key][$k] + $item[$k];
        }
    }
}

print_r(array_values($r));

是否要将每个数组的字段求和,并生成一个乘积数组?您可以使用foreach循环轻松完成此操作,也许您可以尝试先自己完成此操作,然后我们可以帮助您假设每个原始数组具有相同的长度吗?是@joshuamiller…长度将相同如果源数组是多维的,则您的
$yourArray
不是(;OP;源数组是多维的,$yourArray不是(-;如果之前未声明$temp[0]['v1']或['v2']或['v3'],则+=运算符将抛出未定义的变量通知。
<?php
        $merged = array();
        $res =  array('a1'=>12,'v1'=>3100.00,'v2'=>186.00,'v3'=>186.00);
        $res1 = array('a1'=>12,'v1'=>1200.00,'v2'=>72.00,'v3'=>72.00);

        foreach ([$res, $res1] as $a) {                             // iterate both arrays
            foreach ($a as $key => $value) {                     // iterate all keys+values
                $merged[$key] = $value + (isset($merged[$key]) ? $merged[$key] : 0);   // merge and add
            }
        }

    print "<pre>";
    print_r($merged); 
    die;
    ?>
Try This code ,
foreach($value as $i=>$v) {
    $temp[0]['a1'] = $v['a1'];
    $temp[0]['v1'] += $v['v1'];
    $temp[0]['v2'] += $v['v2'];
    $temp[0]['v3'] += $v['v3'];

}
<?php
$a = [
    [
        'a1' => 12,
        'v1' => 3100.00,
        'v2' => 186.00,
        'v3' => 186.00,
    ],
    [
        'a1' => 12,
        'v1' => 1200.00,
        'v2' => 72.00,
        'v3' => 72.00,
    ],
    [
        'a1' => 13,
        'v1' => 2100.00,
        'v2' => 386.00,
        'v3' => 386.00,
    ],
    [
        'a1' => 13,
        'v1' => 1200.00,
        'v2' => 72.00,
        'v3' => 72.00,
    ]
];

$r = [];
foreach ($a as $item) {
    $key = $item['a1'];
    if (empty($r[$key]))
        $r[$key] = $item;
    else {
        foreach ($item as $k => $v) {
            if ($k !== 'a1')
                $r[$key][$k] = empty($r[$key][$k]) ? $item[$k] : $r[$key][$k] + $item[$k];
        }
    }
}

print_r(array_values($r));