用PHP将HTML表单数据插入MySQL
我正在尝试创建一个简单的留言板MySQL数据库，在这个数据库中，您可以在一个页面上编写评论并通过HTML表单提交，并且在提交评论后在另一个页面上查看所有评论 我的问题是HTML表单中的两个字段没有插入MySQL数据库，这导致我的view all reviews页面缺少名称和标题 当我用PHP进行MySQL查询时，代码可以正常工作，但我需要HTML表单才能工作 HTML表单：用PHP将HTML表单数据插入MySQL,php,mysql,post,forms,http-post,Php,Mysql,Post,Forms,Http Post,我正在尝试创建一个简单的留言板MySQL数据库，在这个数据库中，您可以在一个页面上编写评论并通过HTML表单提交，并且在提交评论后在另一个页面上查看所有评论 我的问题是HTML表单中的两个字段没有插入MySQL数据库，这导致我的view all reviews页面缺少名称和标题 当我用PHP进行MySQL查询时，代码可以正常工作，但我需要HTML表单才能工作 HTML表单： <form action ="process.php" method = "post">
<form action ="process.php" method = "post">
<fieldset>
<legend>Review Field</legend>
Reviewer Name: <br />
<input type="text" name "name" id = "name"><br />
Title of Review:<br />
<input type="text" name "title" id = "title"><br />
Enter your review below:
<!--Textbox start-->
<textarea name="body" id = "body" rows="10" cols="100">
</textarea>
<!--Textbox end-->
<br />
<input type="submit" name = "submit" id="submit">
<br />
</fieldset>
</form>
<?php // Create a database connection.
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "password";
$dbname = "ya_reviews";
$connection = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname);
//Test if connection occurred.
if (mysqli_connect_errno()) {
die("Database connection failed: " .
mysqli_connect_error() .
" (" . mysqli_connect_errno() . ")"
);
}
//Perform database query
$name = $_POST['name'];
$title = $_POST['title'];
$body = $_POST['body'];
//This function will clean the data and add slashes.
// Since I'm using the newer MySQL v. 5.7.14 I have to addslashes
$name = mysqli_real_escape_string($connection, $name);
$title = mysqli_real_escape_string($connection, $title);
$body = mysqli_real_escape_string($connection, $body);
//This should retrive HTML form data and insert into database
$query = "INSERT INTO reviews (name, title, body)
VALUES ('".$_POST["name"]."','".$_POST["title"]."','".$_POST["body"]."')";
$result = mysqli_query($connection, $query);
//Test if there was a query error
if ($result) {
//SUCCESS
header('Location: activity.php');
} else {
//FAILURE
die("Database query failed. " . mysqli_error($connection));
//last bit is for me, delete when done
}
mysqli_close($connection);
?>
<?php
//This will fetch the data from the database
$query = "SELECT * FROM reviews";
$result = mysqli_query($connection, $query);
//Test if there was a query error
if (!$result) {
die("Database query failed.");
}
// This will let me display the data.
// The loop will be spilt so I can format with HTML
while ($row = mysqli_fetch_assoc($result)) {
//output data from each row
?>
Name: <?php echo $row["name"] . "<br />"; ?>
Title: <?php echo $row["title"] . "<br />"; ?>
Review: <?php echo $row["body"] . "<br />";
echo "<hr>"; ?>
<?php
} ?>
审查领域
审核人姓名：
审查标题：
在下面输入您的评论：
<form action ="process.php" method = "post">
<fieldset>
<legend>Review Field</legend>
Reviewer Name: <br />
<input type="text" name "name" id = "name"><br />
Title of Review:<br />
<input type="text" name "title" id = "title"><br />
Enter your review below:
<!--Textbox start-->
<textarea name="body" id = "body" rows="10" cols="100">
</textarea>
<!--Textbox end-->
<br />
<input type="submit" name = "submit" id="submit">
<br />
</fieldset>
</form>
<?php // Create a database connection.
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "password";
$dbname = "ya_reviews";
$connection = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname);
//Test if connection occurred.
if (mysqli_connect_errno()) {
die("Database connection failed: " .
mysqli_connect_error() .
" (" . mysqli_connect_errno() . ")"
);
}
//Perform database query
$name = $_POST['name'];
$title = $_POST['title'];
$body = $_POST['body'];
//This function will clean the data and add slashes.
// Since I'm using the newer MySQL v. 5.7.14 I have to addslashes
$name = mysqli_real_escape_string($connection, $name);
$title = mysqli_real_escape_string($connection, $title);
$body = mysqli_real_escape_string($connection, $body);
//This should retrive HTML form data and insert into database
$query = "INSERT INTO reviews (name, title, body)
VALUES ('".$_POST["name"]."','".$_POST["title"]."','".$_POST["body"]."')";
$result = mysqli_query($connection, $query);
//Test if there was a query error
if ($result) {
//SUCCESS
header('Location: activity.php');
} else {
//FAILURE
die("Database query failed. " . mysqli_error($connection));
//last bit is for me, delete when done
}
mysqli_close($connection);
?>
<?php
//This will fetch the data from the database
$query = "SELECT * FROM reviews";
$result = mysqli_query($connection, $query);
//Test if there was a query error
if (!$result) {
die("Database query failed.");
}
// This will let me display the data.
// The loop will be spilt so I can format with HTML
while ($row = mysqli_fetch_assoc($result)) {
//output data from each row
?>
Name: <?php echo $row["name"] . "<br />"; ?>
Title: <?php echo $row["title"] . "<br />"; ?>
Review: <?php echo $row["body"] . "<br />";
echo "<hr>"; ?>
<?php
} ?>
您的HTML属性语法不正确。它在属性
和值
之间缺少=
符号
将name“name”
更改为name=“name”
，将name“title”更改为name=“title”
审查标题：
另外，在insert
过程中，您没有使用转义值
在插入查询中使用$name
而不是$\u POST[“name”]
。标题和正文值也是如此。您的HTML属性语法不正确。它在属性
和值
之间缺少=
符号
将name“name”
更改为name=“name”
，将name“title”更改为name=“title”
审查标题：
另外，在insert
过程中，您没有使用转义值
在插入查询中使用$name
而不是$\u POST[“name”]
。标题和正文值也是一样。我想你搞乱了HTML的语法
<form action ="process.php" method = "post">
<fieldset>
<legend>Review Field</legend>
Reviewer Name: <br />
<input type="text" name="name" id = "name"><br />
Title of Review:<br />
<input type="text" name="title" id = "title"><br />
Enter your review below:
<!--Textbox start-->
<textarea name="body" id = "body" rows="10" cols="100">
</textarea>
<!--Textbox end-->
<br />
<input type="submit" name = "submit" id="submit">
<br />
</fieldset>
</form>
审查领域
审核人姓名：
审查标题：
在下面输入您的评论：
它肯定会成功的 我想你把HTML的语法搞砸了
<form action ="process.php" method = "post">
<fieldset>
<legend>Review Field</legend>
Reviewer Name: <br />
<input type="text" name="name" id = "name"><br />
Title of Review:<br />
<input type="text" name="title" id = "title"><br />
Enter your review below:
<!--Textbox start-->
<textarea name="body" id = "body" rows="10" cols="100">
</textarea>
<!--Textbox end-->
<br />
<input type="submit" name = "submit" id="submit">
<br />
</fieldset>
</form>
审查领域
审核人姓名：
审查标题：
在下面输入您的评论：
它肯定会成功的 问题在于HTML中的name属性不正确
<input type="text" name="name" id = "name"><br />
<input type="text" name="title" id = "title"><br />
问题在于HTML中的name属性不正确
<input type="text" name="name" id = "name"><br />
<input type="text" name="title" id = "title"><br />
Yo，您只是缺少一些语法，因此在从这些元素收集数据时会产生错误
<input type="text" name "title" id = "title">
您缺少name参数中的“=”符号，只是缺少一些语法，因此在从这些元素收集数据时会产生错误
<input type="text" name "title" id = "title">
您缺少名称参数中的“=”符号请在mysqli中使用预置语句-别忘了更改密码请在mysqli中使用预置语句-别忘了更改密码谢谢语法错误和混淆变量似乎是我的死敌。>非常感谢！^^语法错误和混淆变量似乎是我的死敌。>