使用php从URL获取JSON对象

我已经从这个网址

[{"user_id":"3932131","username":"DanielDimitrov","count300":"1677134","count100":"239025","count50":"41207","playcount":"17730","ranked_score":"1413977663","total_score":"7355146958","pp_rank":"35848","level":"95.5852","pp_raw":"1582.26","accuracy":"97.88556671142578","count_rank_ss":"42","count_rank_s":"337","count_rank_a":"120","country":"BG","events":[]}]

我的php就是这个

$json = file_get_contents('url');
    $obj = json_decode($json);
    echo $obj->user_id;
    echo 'Username: '.$obj['username'].'<br>';
    echo 'PP: '.(int)$obj['pp_raw'].'<br>';
    echo 'Level: '.(int)$obj['level'].'<br>';
    echo 'Play count: '.$obj['playcount'].'<br>';

我试图从url和代码运行中删除括号，但我得到了括号。。。如何删除它们？

$obj是一个包含1个元素的数组

简短的修正是，先执行$obj=$obj[0]

---

然后您可以执行$obj[user_id]等操作。

哪个括号？你想做什么？您遇到的确切错误是什么？

<?php
$json = '[{"user_id":"3932131","username":"DanielDimitrov","count300":"1677134","count100":"239025","count50":"41207","playcount":"17730","ranked_score":"1413977663","total_score":"7355146958","pp_rank":"35848","level":"95.5852","pp_raw":"1582.26","accuracy":"97.88556671142578","count_rank_ss":"42","count_rank_s":"337","count_rank_a":"120","country":"BG","events":[]}]';
    $in = array("[{", "}]");
    $out = array("{", "}");
    $obj = json_decode(str_replace($in, $out, $json));
    echo $obj->user_id;
    echo 'Username: '.$obj->username.'<br>';
    echo 'PP: '.(int)$obj->pp_raw.'<br>';
    echo 'Level: '.(int)$obj->level.'<br>';
    echo 'Play count: '.$obj->playcount.'<br>';
?>