Php 从mysql选择中排除空数据

排除空数据时遇到问题，我只想提取包含

discord\u id

数据的行。以下是我的代码：

<?php
$con=mysqli_connect("localhost","site","password","table");

if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

$result = mysqli_query($con,"SELECT * FROM core_members");

while($row = mysqli_fetch_array($result))
  {
  echo $row['name'] . " " . $row['discord_id']; 
  echo "<br />";
  }

mysqli_close($con);

?>

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将其作为条件添加到

WHERE

子句中：

SELECT * FROM core_members where discord_id is not null

您必须像下面这样使用：-

$result = mysqli_query($con,"SELECT * FROM `core_members` WHERE `discord_id` IS NOT NULL");

---

只需添加一个

不为空

条件：

$result = 
    mysqli_query($con, "SELECT * FROM core_members WHERE discord_id IS NOT NULL");

---

将以下where子句添加到代码中：-

其中discord_id不为空

完整Select语句：

SELECT * FROM core_members where discord_id is not null;

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您想在PHP或mysql端执行此操作吗？Zen很乐意帮助您：）：）