在PHP中从给定数组创建数组

我的结果是

array(
    (int) 0 => array(
        'parent_id' => '3',
        'student_name' => null,
        'date' => '2014-07-16',
        'total_hrs' => '02:00',
        'subject_price' => '500'
    ),
    (int) 1 => array(
        'parent_id' => '3',
        'student_name' => null,
        'date' => '2014-07-16',
        'total_hrs' => '02:00',
        'subject_price' => '500'
    ),
    (int) 2 => array(
        'parent_id' => '4',
        'student_name' => null,
        'date' => '2014-07-17',
        'total_hrs' => '02:00',
        'subject_price' => '500'
    ),
    (int) 3 => array(
        'parent_id' => '3',
        'student_name' => null,
        'date' => '2014-07-23',
        'total_hrs' => '02:00',
        'subject_price' => '400'
    ),
    (int) 4 => array(
        'parent_id' => '3',
        'student_name' => null,
        'date' => '2014-07-23',
        'total_hrs' => '02:00',
        'subject_price' => '400'
    ),
    (int) 5 => array(
        'parent_id' => '3',
        'student_name' => null,
        'date' => '2014-08-04',
        'total_hrs' => '02:00',
        'subject_price' => '500'
    ),
    (int) 6 => array(
        'parent_id' => '4',
        'student_name' => null,
        'date' => '2014-08-04',
        'total_hrs' => '02:00',
        'subject_price' => '500'
    ),
    (int) 7 => array(
        'parent_id' => '3',
        'student_name' => null,
        'date' => '2014-08-11',
        'total_hrs' => '02:00',
        'subject_price' => '500'
    ),
    (int) 8 => array(
        'parent_id' => '4',
        'student_name' => null,
        'date' => '2014-08-11',
        'total_hrs' => '02:00',
        'subject_price' => '500'
    ),
    (int) 9 => array(
        'parent_id' => '3',
        'student_name' => null,
        'date' => '2014-08-18',
        'total_hrs' => '02:00',
        'subject_price' => '500'
    ),
    (int) 10 => array(
        'parent_id' => '4',
        'student_name' => null,
        'date' => '2014-08-18',
        'total_hrs' => '02:00',
        'subject_price' => '500'
    ),
    (int) 11 => array(
        'parent_id' => '3',
        'student_name' => null,
        'date' => '2014-08-25',
        'total_hrs' => '02:00',
        'subject_price' => '500'
    ),
    (int) 12 => array(
        'parent_id' => '4',
        'student_name' => null,
        'date' => '2014-08-25',
        'total_hrs' => '02:00',
        'subject_price' => '500'
    )
)

我希望得到以下结果，以便根据家长id和月份得到“主题价格”的总和

array(
    '07-2014' => array(
        '3 (i.e Parent id)' => '1500 (i.e. sum of subject for parent 3 and month 07-2014)',
        '4 (i.e Parent id)' => '800 (i.e. sum of subject for parent 3 and month 07-2014)',
    ),
    '08-2014' => array(
        '3 (i.e Parent id)' => '2000 (i.e. sum of subject for parent 3 and month 07-2014)',
        '4 (i.e Parent id)' => '2000 (i.e. sum of subject for parent 3 and month 07-2014)',
    )
)

以下是更新的代码

$sum = array();
    foreach ($array_push as $v) {
        if (!isset($sum[date('m-Y', strtotime($v['date']))])) {
            $sum[date('m-Y', strtotime($v['date']))] = array();
        }
        if (!isset($sum[date('m-Y', strtotime($v['date']))][$v['parent_id']])) {
            $sum[date('m-Y', strtotime($v['date']))][$v['parent_id']] = 0;
        }
        $sum[date('m-Y', strtotime($v['date']))][$v['subject_price']] += $v['subject_price'];
        $sum[date('m-Y', strtotime($v['date']))][$v['parent_id']]++;
    }

结果我得到了。

排列(
'07-2014'=>阵列(
（int）3=>（int）4，
（int）500=>（int）1500，
（int）4=>（int）1，
（int）400=>（int）800
),
“08-2014”=>阵列(
（int）3=>（int）4，
（int）500=>（int）4000，
（int）4=>（int）4
)
)

有没有什么方法可以让我把密钥作为父id，把主题价格的总和作为那个月的值

你能建议一下怎么做吗。谢谢你的帮助。如果你需要更多的信息，请告诉我

提前感谢。

这应该可以做到（假设$array是您的输入数组）：

---

尝试使用sql查询，如：

select attr1, attr2, sum(attr2) as sum from myTable group by attr1, attr2;

---

然后按需要使用它

注意，输出数组中的索引应该忽略天。感谢您的回复。我编辑了我的代码。请参阅我收到的回复。我根据您在问题中添加的内容再次编辑了它。非常感谢您这正是我想要的。谢谢您的评论。但是，在我的应用程序中，不可能使用group by来完成，因为我正在对数据进行序列化，因此我面临着这个问题

$printable = array();
foreach($sum as $d => $g) {
    $printable[$d] = array();
    foreach($g as $p => $v) {
        $printable[$d][sprintf('%s (i.e Parent id)', $p)] = sprintf('%d (i.e. sum of subject for parent %s and month %s)', $v, $p, $d)
    }
}

var_export($printable);

select attr1, attr2, sum(attr2) as sum from myTable group by attr1, attr2;