为什么我的PHP代码不更新SQL

有人知道为什么这个PHP代码不更新列图片吗？它会更新其余的列图片，但不更新图片列。它是用来更新用户信息的，所以电子邮件地址、密码和图片我对PHP很陌生，所以我不知道在查找错误时要查找什么

    <?php 

    require("common.php"); 

    if(empty($_SESSION['user'])) 
    { 
        header("Location: login.php"); 

        die("Redirecting to login.php"); 
    } 

    if(!empty($_POST)) 
    { 
        if(!filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)) 
        { 
            die("Invalid E-Mail Address"); 
        } 

        if($_POST['email'] != $_SESSION['user']['email']['picture']) 
        { 
            $query = " 
                SELECT 
                    1 
                FROM users 
                WHERE 
                    email = :email
                    picture = :picture
            "; 

            $query_params = array( 
                ':email' => $_POST['email'] 
            ); 

            try 
            { 
                $stmt = $db->prepare($query); 
                $result = $stmt->execute($query_params); 
            } 
            catch(PDOException $ex) 
            { 
                die("Failed to run query: " . $ex->getMessage()); 
            } 

            $row = $stmt->fetch(); 
            if($row) 
            { 
                die("This E-Mail address is already in use"); 
            } 
        } 

        if(!empty($_POST['password'])) 
        { 
            $salt = dechex(mt_rand(0, 2147483647)) . dechex(mt_rand(0, 2147483647)); 
            $password = hash('sha256', $_POST['password'] . $salt); 
            for($round = 0; $round < 65536; $round++) 
            { 
                $password = hash('sha256', $password . $salt); 
            } 
        } 
        else 
        { 
            $password = null; 
            $salt = null; 
        } 

        $query_params = array( 
            ':email' => $_POST['email'], 
            ':user_id' => $_SESSION['user']['id'], 
            ':picture' => $_POST['picture'], 
        ); 

        if($password !== null) 
        { 
            $query_params[':password'] = $password; 
            $query_params[':salt'] = $salt; 
        } 

        $query = " 
            UPDATE users 
            SET 
                email = :email 
                picture = :picture
        "; 

        if($password !== null) 
        { 
            $query .= " 
                , password = :password 
                , salt = :salt 
            "; 
        } 

        $query .= " 
            WHERE 
                id = :user_id 
        "; 

        try 
        { 
            // Execute the query 
            $stmt = $db->prepare($query); 
            $result = $stmt->execute($query_params); 
        } 
        catch(PDOException $ex) 
        { 
            die("Failed to run query: " . $ex->getMessage()); 
        } 

        $_SESSION['user']['email']['picture'] = $_POST['email']; 

        header("Location: private.php"); 

        die("Redirecting to private.php"); 
    } 

?> 

---

您的更新声明中：email后缺少逗号

$query = " 
            UPDATE users 
            SET 
                email = :email 
                picture = :picture
        "; 

应该是

$query = " 
        UPDATE users 
        SET 
            email = :email,  
            picture = :picture
    "; 

编辑：除此之外，您在第一次查询中还缺少一个参数：

        $query = " 
            SELECT 
                1 
            FROM users 
            WHERE 
                email = :email
                picture = :picture
        "; 

        $query_params = array( 
            ':email' => $_POST['email'] 
        ); 

请注意，您在查询参数中仅应用了：email，但您的查询同时需要：email和：picture

您需要从$query中删除picture=：picture，或者将“：picture'=>$\u POST['picture']添加到$query\u参数中，您缺少一个、

你需要把它改成

$query = " 
    UPDATE users 
    SET 
        email = :email, 
        picture = :picture
";

---

+1对于实际使用准备好的语句和验证输入，您需要在email=：email picture=：picture之间添加逗号。您是否正在检查设置了$_POST['picture']吗？还需要在SELECT的WHERE子句中输入AND，否？您的SELECT查询在in中有两个参数：email和：picture；但你只是绑定：电子邮件。我认为你的/a问题在于，你的列名1是一个从用户中选择1的单个数字，我引用的标识符可能以数字开头，但除非引用，否则可能不仅仅由数字组成。-@user3116240 OK，我刚刚更新了它，它似乎仍在运行检查，以确保您的表单输入有名称=图片，拼写正确。您确定picture不是文件吗？请在$query语句之前尝试使用var\u dump$\u POST['picture']，查看其值。该变量可能为空。检查您的html以查看是否有输入名称=pictureSeems，如变量为空，请验证您的html为上面提到的@Leng。

$query = " 
    UPDATE users 
    SET 
        email = :email, 
        picture = :picture
";