Php 如何获取所选选项值（codeigniter）

我有带选项的表单，当我想添加时，值为空。我想问的是如何获得我选择的值

我的表格：

<select name="student_id" class="form-control" data-validate="required" id="student_id"
                      data-message-required="<?php echo get_phrase('value_required');?>"
                        onchange="return get_class_sections(this.value)">
                                    <option value=""><?php echo get_phrase('Selecteaz&#259;_un_student');?></option>
                                    <?php
                      $stare='0';
                      $classes = $this->db->get_where('disertatie_studenti',array('retrasi'=>$stare))->result_array();
                      foreach($classes as $row):
                        ?>
                                      <option value="<?php echo $this->db->get_where('disertatie_studenti' , array('student_id' => $row['student_id']))->row()->name;?>">
                            <?php echo $row['name'];?>
                                                  </option>
                                      <?php
                      endforeach;
                      ?>
                      </select>

错误消息：

INSERT INTO `disertatie_corectura` (`student_id`, `corectura`, `timestamp`, `year`) VALUES (NULL, '2554', 1574456889, '2019-2020')

您不认为最好在

标记之前运行查询，然后

echo

您检查的值您在foreach上检索正确的值吗？

INSERT INTO `disertatie_corectura` (`student_id`, `corectura`, `timestamp`, `year`) VALUES (NULL, '2554', 1574456889, '2019-2020')

<option value="<?php echo $this->db->get_where('disertatie_studenti' , array('name' => $row['name']))->row()->student_id;?>">
                                <?php echo $row['name'];?>