Php 原则2使用四个表将两个表与第三个表连接起来

我很困惑，花了两天的时间来寻找这个问题的答案，什么都没有。 我已经有5张桌子了

• 语言->id，iso\U代码
• I18n_实体->id
• I18n\u字符串->id，I18n\u实体\u id，语言\u id，文本
• 产品->标识，i18n\u实体\u标识（唯一）
• 类别->id，i18n\u实体\u id（唯一）

我需要做两种方法

getProductByName（语言$Language，$name）

SELECT c.*, i18s.text
FROM category as c
INNER JOIN I18n_String AS i18s ON i18s.i18n_entity_id = c.i18n_entity_id AND i18s.language_id = :language_id
WHERE i18s.text = :name

namespace Application\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * Product
 *
 * @ORM\Table(name="product", uniqueConstraints={@ORM\UniqueConstraint(name="product_i18n_entity_id_unique", columns={"i18n_entity_id"})})
 * @ORM\Entity
 */
class Product {
    /**
     * @var integer
     *
     * @ORM\Column(name="id", type="integer", nullable=false)
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="SEQUENCE")
     * @ORM\SequenceGenerator(sequenceName="product_id_seq", allocationSize=1, initialValue=1)
     */
    private $id;

    /**
     * @var \Application\Entity\I18nEntity
     *
     * @ORM\ManyToOne(targetEntity="Application\Entity\I18nEntity")
     * @ORM\JoinColumns({
     *   @ORM\JoinColumn(name="i18n_entity_id", referencedColumnName="id")
     * })
     */
    private $i18nEntity;
    ...

因此，用于此目的的普通PostgreSQL查询是：

SELECT p.*, i18s.text
FROM product as p
INNER JOIN I18n_String AS i18s ON i18s.i18n_entity_id = p.i18n_entity_id AND i18s.language_id = :language_id
WHERE i18s.text = :name

getCategoryByName（语言$Language，$name）

SELECT c.*, i18s.text
FROM category as c
INNER JOIN I18n_String AS i18s ON i18s.i18n_entity_id = c.i18n_entity_id AND i18s.language_id = :language_id
WHERE i18s.text = :name

namespace Application\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * Product
 *
 * @ORM\Table(name="product", uniqueConstraints={@ORM\UniqueConstraint(name="product_i18n_entity_id_unique", columns={"i18n_entity_id"})})
 * @ORM\Entity
 */
class Product {
    /**
     * @var integer
     *
     * @ORM\Column(name="id", type="integer", nullable=false)
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="SEQUENCE")
     * @ORM\SequenceGenerator(sequenceName="product_id_seq", allocationSize=1, initialValue=1)
     */
    private $id;

    /**
     * @var \Application\Entity\I18nEntity
     *
     * @ORM\ManyToOne(targetEntity="Application\Entity\I18nEntity")
     * @ORM\JoinColumns({
     *   @ORM\JoinColumn(name="i18n_entity_id", referencedColumnName="id")
     * })
     */
    private $i18nEntity;
    ...

我知道可以通过内部连接i18n_实体作为i18e ON i18e.id=p.i18n_实体，但这是不必要的

问题是：这可以用条令来完成吗？如果可以，如何进行正确的注释和dql

product.php

namespace Application\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * Product
 *
 * @ORM\Table(name="product", uniqueConstraints={@ORM\UniqueConstraint(name="product_i18n_entity_id_unique", columns={"i18n_entity_id"})})
 * @ORM\Entity
 */
class Product {
    /**
     * @var integer
     *
     * @ORM\Column(name="id", type="integer", nullable=false)
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="SEQUENCE")
     * @ORM\SequenceGenerator(sequenceName="product_id_seq", allocationSize=1, initialValue=1)
     */
    private $id;

    /**
     * @var \Application\Entity\I18nEntity
     *
     * @ORM\ManyToOne(targetEntity="Application\Entity\I18nEntity")
     * @ORM\JoinColumns({
     *   @ORM\JoinColumn(name="i18n_entity_id", referencedColumnName="id")
     * })
     */
    private $i18nEntity;
    ...

i18nEntityId.php

<?php

namespace Application\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * I18nEntity
 *
 * @ORM\Table(name="i18n_entity", indexes={@ORM\Index(name="i18n_entity_status_index", columns={"status"})})
 * @ORM\Entity
 */
class I18nEntity {
    /**
     * @var integer
     *
     * @ORM\Column(name="id", type="bigint", nullable=false)
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="SEQUENCE")
     * @ORM\SequenceGenerator(sequenceName="i18n_entity_id_seq", allocationSize=1, initialValue=1)
     */
    private $id;
    ...

---

原则旨在从您那里提取所有SQL生成。如果正确配置实体注释，则甚至不需要在中创建此查询DQL@AlexP嗨，我不知道如何为这种情况编写正确的注释，有人能帮我吗？