Php 提交按钮不会将表单数据发送到MySQL数据库

我有一个问题，可能是语法问题，但我似乎无法找出我做错了什么。 我已经创建了一个表单，当我单击submit时，表单中的数据不会发送到我的mysql数据库

这是我的html代码

<div class="content-wrapper">
  <div class="container">
    <div class="row">
      <div class="col-md-10">
        <h1 class="page-head-line">Forms </h1>
      </div>
    </div>
    <div class="row">
      <div class="col-md-10">
        <div class="panel panel-default">
          <div class="panel-heading">
            BASIC  FORM ELEMENTS
          </div>
          <div class="panel-body">
            <form method="post" action="insert.php" >
              <div class="form-group">
                <label for="name">Name</label>
                <input name="name' type="text" class="form-control" id="name" placeholder="Enter your name"  required/>
                                                                                                           </div>
                       <div class="form-group">
                         <label for="project_num">OIT-GIS Project Number</label>
                         <input name="project_num' type="text" class="form-control" id="project_num" placeholder="OIT-GIS Project Number" />
                                                                                                                                         </div>
                                <div class="form-group">
                                  <label for="project_name">Project Name</label>
                                  <input name="name' type="text" class="form-control" id="project_name" placeholder="Project Name" required/>
              </div>
              <div class="form-group">
                <label for="easyvista">EasyVista Ticket Number</label>
                <input name="easyvista' type="text" class="form-control" id="easyvista" placeholder="EasyVista Ticket Number" />
                       </div>
                       <div class="form-group">
                         <label for="agency">Requestor/Agency</label>
                         <input name="agency' type="text" class="form-control" id="agency" placeholder="Requestor or Agency" />
                                </div>
                                <div class="form-group">
                                  <label for="description">Description of Work:</label>
                                  <input name="description' type="text" class="form-control" id="agency" placeholder="Description" />

              </div>
              <div class="form-group">
                <label for="input-date">Enter Today Date</label>
                <input name="input-date' type="date" value="">
                         <span class="result"></span>
                       </div>
                       <div class="form-group">
                         <div class="col-md-10">
                           <input id="submit" name="submit" type="submit" class="btn btn-primary">
                         </div>
                       </div>
            </form>


          </div>
        </div>

这是我的php

<?php

echo $POST;
  error_reporting(E_ALL);
  ini_set('display_errors', 1);
    include("../includes/config.php");

 if (isset($_POST['submit'])) {
        echo $_POST['submit'];
        $name = $_POST['name'];
        $projectnum = $_POST['project_num'];
        $projectname = $_POST['project_name'];
        $easyvista = $_POST['easyvista'];
        $agency = $_POST['agency'];
        $description = $_POST['description'];
        $startDate = $_POST['input-date'];

    $sql="INSERT INTO statusreport(name, project_num, project_name, easyvista, agency, description)
            VALUES
            ('$name','$projectnum', '$projectname', '$easyvista', '$agency', '$description')";         

    if (!mysqli_query($conn, $sql))
      {
      die('Error: ' . mysqli_connect_error($conn));
      }
    echo "Entry is recored <br/>";
    echo "Name:", $name, "<br/>";
    echo "test..................<br/>", $name;
     /*header("location: http://10.1.7.129//gisadmin/admin/forms.php");*/

    //echo "<script>setTimeout(\"location.href = 'http://10.1.7.129//gisadmin/admin/forms.php';\",700);</script>";
    mysqli_query($conn, $sql);
}
else {
    echo "No data";
}
?>

任何帮助都将不胜感激。

---

谢谢

这里混合了单引号和双引号，名称属性用双引号打开值，用单引号关闭值，应如下所示：

<form method="post" action="insert.php" >
    <div class="form-group">
        <label for="name">Name</label>
        <input name="name" type="text" class="form-control" id="name" placeholder="Enter your name"  required/>
    </div>
    <div class="form-group">
        <label for="project_num">OIT-GIS Project Number</label>
        <input name="project_num" type="text" class="form-control" id="project_num" placeholder="OIT-GIS Project Number" />
    </div>
    <div class="form-group">
        <label for="project_name">Project Name</label>
        <input name="project_name" type="text" class="form-control" id="project_name" placeholder="Project Name" required/>
    </div>
    <div class="form-group">
        <label for="easyvista">EasyVista Ticket Number</label>
        <input name="easyvista" type="text" class="form-control" id="easyvista" placeholder="EasyVista Ticket Number" />
    </div>
    <div class="form-group">
        <label for="agency">Requestor/Agency</label>
        <input name="agency" type="text" class="form-control" id="agency" placeholder="Requestor or Agency" />
    </div>
    <div class="form-group">
        <label for="description">Description of Work:</label>
        <input name="description" type="text" class="form-control" id="agency" placeholder="Description" />

    </div>
    <div class="form-group">
        <label for="input-date">Enter Today Date</label>
        <input name="input-date" type="date" value="">
        <span class="result"></span>
    </div>
    <div class="form-group">
        <div class="col-md-10">
            <input id="submit" name="submit" type="submit" class="btn btn-primary">
        </div>
    </div>
</form>

---

该行是错误的，在该代码之前没有名为$POST的变量。

您是否收到了成功消息，但数据库未得到更新或出现了全部错误

1检查双引号和单引号

  <div class="form-group">
      <label for="name">Name</label>
      <input name="name" type="text" class="form-control" id="name" placeholder="Enter your name"  required/>
  </div> 

这是正确的还是错误的

三,

应该是

 <label for="project_name">Project Name</label>
 <input name="project_name" type="text" 

---

这是一个语法错误，首先是echo$POST；它会给你一个未定义的$change通知，然后name = xxx’-复制/粘贴得到了你最好的。这是如果它甚至使它在大门外山姆@ JayBurgCARDIVE学习关于使用PDO的语句，并考虑使用。我收到一个错误，在第10行的C:\Program Files x86\Ampps\www\gisadmin\admin\insert.php中显示Send Notice:Undefined index:name in C:\Program Files x86\Ampps\www\gisadmin\admin\insert.php第11行的通知：Undefined index:project\u name in C:\Program Files x86\Ampps\www\gisadmin\admin\insert.php on第12行include../includes/config.php；你试过单引号和双引号解决问题吗？e、 是的，塔克斯卡拉帮我做了那部分。好的。。。项目名称谢谢你的剪报，它很有帮助。我没有意识到我把我的引语弄混了。但是，我仍然收到一个字段的错误通知：未定义索引：C:\Program Files x86\Ampps\www\gisadmin\admin\insert.php中的project\u name，在第10行如何找出导致此问题的原因？是的，检查编辑，您将以名称而不是project\u name发送输入。记住，输入的name属性将是$\u POST数组中的键。是的，我明白你的意思。谢谢，这非常有帮助，而且效果很好。

include("../includes/config.php");

<label for="project_name">Project Name</label> 
<input name="name' type="text" 

 <label for="project_name">Project Name</label>
 <input name="project_name" type="text"