MYSQL&；PHP while循环在输出前检查上一行和下一行

我需要检查下一个和上一个MYSQL行/循环（相对于当前while循环）的图像大小条件是否为true，并根据该条件，使用PHP安排当前循环的布局

为了测试和验证代码是否正常工作，我正在检索每行的图像大小，只想输出每个循环的布局条件以及post ID

下面的代码对于当前while循环以及下一行项目都可以正常工作，但是对于上一行项目，我得到了相同的常量值

我的错在哪里？有没有更好/更简单的方法？也许是为了避免多次查询

<?php
$sql = "SELECT * FROM posts WHERE image_featured!='' ORDER BY id DESC LIMIT 5";
$query = mysqli_query($connection, $sql);

while($row = mysqli_fetch_array($query)){
$id = $row["id"];
$current_width = $row["width"];
$current_height = $row["height"];
if ($current_width > $current_height){
$current_layout = 'horizontal';
} // end if
if ($current_width == $current_height){
$current_layout = 'square';
} // end if
if ($current_width < $current_height){
$current_layout = 'vertical';
} // end if

echo 'Current: '.$current_layout.' (ID: '.$id.')<br/>';

$nextsql = "SELECT * FROM posts WHERE id > $id AND image_featured!='' LIMIT 1"; 
$nextquery = mysqli_query($connection, $nextsql);
if(mysqli_num_rows($nextquery) > 0) {
while($nextrow = mysqli_fetch_array($nextquery)){
$next_id  = $nextrow['id'];
$next_width = $nextrow["width"];
$next_height = $nextrow["height"];
if ($next_width > $next_height){
$next_layout = 'horizontal';
} // end if
if ($next_width == $next_height){
$next_layout = 'square';
} // end if
if ($next_width < $next_height){
$next_layout = 'vertical';
} // end if
echo 'Next: '.$next_layout.' (ID: '.$next_id.')<br/>';
} // end while
} // end if

$previoussql= "SELECT * FROM posts WHERE id < $id AND image_featured!='' LIMIT 1"; 
$previousquery = mysqli_query($connection, $previoussql);
if(mysqli_num_rows($previousquery) > 0) {
while($previousrow = mysqli_fetch_array($previousquery)){
$previous_id  = $previousrow['id'];
$previous_width = $previousrow["width"];
$previous_height = $previousrow["height"];
if ($previous_width > $previous_height){
$previous_layout = 'horizontal';
} // end if
if ($previous_width == $previous_height){
$previous_layout = 'square';
} // end if
if ($previous_width < $previous_height){
$previous_layout = 'vertical';
} // end if
echo 'Previous: '.$previous_layout.' (ID: '.$previous_id.')<br/>';
} // end while
} // end if

echo '<hr/>';

} // end while 1
?>

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也许您需要添加到查询顺序中，因为从表结果开始，它总是给您相同的解决方案

$previoussql= "SELECT * FROM posts WHERE id < $id AND image_featured!='' ORDER BY id DESC LIMIT 1"; 

$previoussql=“从id<$id和图像特色的帖子中选择*！=”“按id排序描述限制1”；

---

或者可能是ASC，因为我不知道你的表和结果集，所以你得到了

巴哈哈，天哪，我不敢相信这就是原因！工作起来很有魅力！非常感谢！！：）

$previoussql= "SELECT * FROM posts WHERE id < $id AND image_featured!='' ORDER BY id DESC LIMIT 1";