Php 如何从数组/对象中获取值

我调用upload函数，它返回一个变量。当我执行

var\u dump（$x）

时，它显示以下内容：

{"files":[{"name":"1004046_469695273124093_104592888_n_1_28860.jpg","size":0,"type":"image\/jpeg","error":"abort","delete_url":"http:\/\/www.xxx.com\/upload\/uploader\/server\/php\/?file=1004046_469695273124093_104592888_n_1_28860.jpg","delete_type":"DELETE"}]}array(1) {
["files"]=>
    array(1) {
     [0]=> object(stdClass)#24 (6) {
     ["name"]=> string(47) "1004046_469695273124093_104592888_n_1_28860.jpg"
     ["size"]=> int(0)
     ["type"]=> string(10) "image/jpeg"
     ["error"]=> string(5) "abort"
     ["delete_url"]=> string(104) "http://www.xxx.com/upload/uploader/server/php/?file=1004046_469695273124093_104592888_n_1_28860.jpg"
     ["delete_type"]=> string(6) "DELETE"
    }
 }
}

我尝试了

var\u dump（json\u decode（$x））

，结果为空

我的问题是如何从中获取值名称

尝试了以下两种方法：

echo $x->files[0]->name;
echo " ********************** ";
echo $x['files'][0]->name;
echo " ********************** ";

结果是

{"files":[{"name":"1004046_469695273124093_104592888_n_1_14299.jpg","size":78289,"type":"image\/jpeg","url":"http:\/\/www.xxx.com\/upload\/uploader\/server\/php\/files\/1004046_469695273124093_104592888_n_1_14299.jpg","thumbnail_url":"http:\/\/www.xxx.com\/upload\/uploader\/server\/php\/files\/thumbnail\/1004046_469695273124093_104592888_n_1_14299.jpg","delete_url":"http:\/\/www.xxx.com\/upload\/uploader\/server\/php\/?file=1004046_469695273124093_104592888_n_1_14299.jpg","delete_type":"DELETE"}]}{"files":[{"name":"1004046_469695273124093_104592888_n_1_12920.jpg","size":0,"type":"image\/jpeg","error":"abort","delete_url":"http:\/\/www.xxx.com\/upload\/uploader\/server\/php\/?file=1004046_469695273124093_104592888_n_1_12920.jpg","delete_type":"DELETE"}]}
********************** 
{"files":[{"name":"1004046_469695273124093_104592888_n_1_15697.jpg","size":0,"type":"image\/jpeg","error":"abort","delete_url":"http:\/\/www.xxx.com\/upload\/uploader\/server\/php\/?file=1004046_469695273124093_104592888_n_1_15697.jpg","delete_type":"DELETE"}]}1004046_469695273124093_104592888_n_1_15697.jpg
********************** 

您是否尝试过：

$name_val = $x->files[0]->name;

您是否尝试过：

$name_val = $x->files[0]->name;

---

我想可能是$x[“文件”][0]->名称。。。顶层元素似乎是一个数组，它首先生成$x？你能提供更多的上下文吗？在第一个数组之前有一个字符串。我做了json_解码，将其拆分为}，然后我将右侧视为一个数组“$x['files'][0]->name”给了我结果，我认为它可能是$x[“files”][0]->name。。。顶层元素似乎是一个数组，它首先生成$x？你能提供更多的上下文吗？在第一个数组之前有一个字符串。我做了json_解码，将其拆分为}，然后我将右侧作为数组“$x['files'][0]->name给了我结果