Php TypeError:settings.data在MOCKJAX中未定义
我有mockjax代码,它给了我错误Php TypeError:settings.data在MOCKJAX中未定义,php,jquery,ajax,mockjax,Php,Jquery,Ajax,Mockjax,我有mockjax代码,它给了我错误 $.mockjax({ url: '*', responseTime: 2000, response: function (settings) { var query = settings.data.query, queryLowerCase = query.toLowerCase(), re = new RegExp('\\b' + $.Autocomplete.u
$.mockjax({
url: '*',
responseTime: 2000,
response: function (settings) {
var query = settings.data.query,
queryLowerCase = query.toLowerCase(),
re = new RegExp('\\b' + $.Autocomplete.utils.escapeRegExChars(queryLowerCase), 'gi'),
suggestions = $.grep(countriesArray, function (country) {
// return country.value.toLowerCase().indexOf(queryLowerCase) === 0;
return re.test(country.value);
}),
response = {
query: query,
suggestions: suggestions
};
this.responseText = JSON.stringify(response);
}
});
这是我的ajax代码
$.ajax({
async: false,
url: 'coments.php?id='+$('#id').val()+'&cmnt='+$('#cmnt').val()+'&type=2',
success: function(data) {
alert('saved');
}
});
它给我错误TypeError:settings.data是未定义的
当我检查控制台时这是一个错误。基本上,请求匹配器只处理数据对象,而不处理查询字符串。您可以像这样更改$.ajax()
调用以匹配您的模拟:
$.ajax({
async: false,
url: 'coments.php',
data: {
id: $('#id').val(),
cmnt: $('#cmnt').val(),
type: 2
}
success: function(data) {
alert('saved');
}
});