PHP根据数据库中的表计算以年为单位的差异总数

我想计算一下总的年差数。情况如下： 我在数据库中有一个表。它包含成员的详细信息，包括他们多年的经验。我想得到总的经验年数。例如，成员的总工作年限为90年。 到目前为止，我已经尝试过了，我得到的只是一个成员的经验

public function getMemberCollectiveExperience() {
        global $config;
        $db = new DatabaseController($config['db']['hostname'], $config['db']['username'], $config['db']['password'], $config['db']['database']);
        $sql = "SELECT * FROM tbl_member WHERE status = 1";
        $result = $db->retrieveRecord($sql);
        if ($result->num_rows > 0) {
            while ($row = $result->fetch_array()) {
                #get member years 
                $memberYears = $row['personal_experience'];
                $currentYear = date('Y');
                $firstResult = $currentYear - $memberYears;
                $total = $firstResult;
            }
            $result = array('count' => $total);
        }
        return $result;
    }

---

您可以尝试此操作以获得所有差异的总和

public function getMemberCollectiveExperience() {
        global $config;
        $total = 0;
        $db = new DatabaseController($config['db']['hostname'], $config['db']['username'], $config['db']['password'], $config['db']['database']);
        $sql = "SELECT * FROM tbl_member WHERE status = 1";
        $result = $db->retrieveRecord($sql);
        if ($result->num_rows > 0) {
            while ($row = $result->fetch_array()) {
                #get member years 
                $memberYears = $row['personal_experience'];
                $currentYear = date('Y');
                $firstResult = $currentYear - $memberYears;
                $total += $firstResult;
            }
            $result = array('count' => $total);
        }
        return $result;
    }

---

显然，出于某种原因，我得到了一个模棱两可的结果。这是因为我将每个成员的默认个人体验设置为0。因此，在循环过程中，出于某种原因，它将这些零视为2017年的当前年份。不过我可能错了。所以我的回答是2108789。 下面的代码修复了这个问题

public function getMemberCollectiveExperience() {
        global $config;
        $total = 0;
        $db = new DatabaseController($config['db']['hostname'], $config['db']['username'], $config['db']['password'], $config['db']['database']);
        $sql = "SELECT personal_experience FROM tbl_member WHERE status = 1";
        $result = $db->retrieveRecord($sql);
        if ($result->num_rows > 0) {
            while ($row = $result->fetch_array()) {
                if ($row['personal_experience'] != null && $row['personal_experience'] != 0) {
                    #get member years 
                    $memberYears = $row['personal_experience'];
                    $firstResult = date('Y') - $memberYears;
                    $total += $firstResult;
                }
            }
            $result = array('count' => $total);
        }
        return $result;
    }

---

谢谢大家

所以你们从查询中得到了多条记录@PhpDevNo-idont。我只有一个会员的工作经验。我需要得到所有成员的总年数@B.Desaith这不是我要问的。顺便说一句，据我所知，您必须在数组中存储数据：：$total[]=$firstResult；我的错。我误解了你的意思。不，我没有从查询中获取多条记录。我刚试过你的建议。它以数组的形式返回