Php 如何获取最新数量的sql子查询

Php 如何获取最新数量的sql子查询,php,mysql,sql,Php,Mysql,Sql,我需要得到每个股票持有人最近的交易金额,而不是他们的交易总额 有两张桌子是存货员 存货表 stid memberid stockistname area_c 1 4 Roger Sp Park 2 6 John Little Garden 3 77 Lily White D 4 32 Meredith Dar

我需要得到每个股票持有人最近的交易金额,而不是他们的交易总额

有两张桌子是存货员

存货表

stid  memberid stockistname     area_c

1      4         Roger           Sp Park
2      6         John            Little Garden
3      77        Lily            White D
4      32        Meredith        Dare street
交易表

trans_id  memberid  trans_type    amount     trans_date

300      4             cp         250        2015-12-01 00:00:56
301      6             cp         100        2015-12-01 01:20:56
302      6             cp         130        2015-12-03 11:03:51
303      77            cp          74        2015-12-03 13:03:51
304      32            cp          25        2015-12-04 11:00:02
305      6             cp         425        2015-12-04 17:00:02
306      4             cp         235        2015-12-05 06:00:02
我的问题是:

SELECT * FROM stockist  LEFT JOIN ( 
SELECT * FROM transactions WHERE trans_type='cp' ORDER BY trans_id DESC LIMIT 1 ) 
transactions ON stockist.memberid=transactions.memberid ORDER BY stockist.stockistname ASC
结果是:

 John $0
 Lily $0
 Meredith $0
 Roger $0
我得到了所有股票持有人的名单但金额为零, 它应该显示

John $425
 Lily $74
 Meredith $25
 Roger $235
实际上,在我的PHP代码中,我的代码看起来像这样,但速度不够快。我想快点

$x=1;
$sql = mysql_query("SELECT * FROM stockist ORDER BY stockistname ASC");
while($row=mysql_fetch_array($sql)){
$memberid=$row['memberid'];
$stockistname=$row['stockistname'];

   $sql2 = mysql_query("SELECT * FROM transactions WHERE memberid='$memberid'  AND  trans_type='cp' ORDER BY trans_id LIMIT 1");
   $row2=mysql_fetch_array($sql2);
   $latest_amount=$row2['amount'];

   echo "<p> $x - $stockistname $ $latest_amount </p>";

$x++;
}
感谢大家

尝试一下:

select stockist.stockistname, amount from
stockist, (select memberid,amount,MAX(trans_date)  from transactions where trans_type='cp' GROUP BY memberid) transactions
where
stockist.memberid=transactions.memberid
ORDER BY stockist.stockistname ASC
试试这个:

select stockist.stockistname, amount from
stockist, (select memberid,amount,MAX(trans_date)  from transactions where trans_type='cp' GROUP BY memberid) transactions
where
stockist.memberid=transactions.memberid
ORDER BY stockist.stockistname ASC

你的限制导致了这个问题。。尝试使用相关查询比较最长日期,如下所示:

SELECT * FROM stockist s
LEFT OUTER JOIN transactions t
 ON(t.memberid = s.memberid and t.trans_type = 'cp')
WHERE t.trans_date = (select max(f.trans_date) from transactions f
                      where f.memberid = t.memberid and f.trans_type = 'cp')

你的限制导致了这个问题。。尝试使用相关查询比较最长日期,如下所示:

SELECT * FROM stockist s
LEFT OUTER JOIN transactions t
 ON(t.memberid = s.memberid and t.trans_type = 'cp')
WHERE t.trans_date = (select max(f.trans_date) from transactions f
                      where f.memberid = t.memberid and f.trans_type = 'cp')
试着按数量订购

SELECT * FROM stockist   
LEFT JOIN  transactions  ON  stockist.memberid = transactions.memberid 
WHERE trans_type='cp' 
GROUP BY stockistname ORDER BY amount DESC LIMIT 1
试着按数量订购

SELECT * FROM stockist   
LEFT JOIN  transactions  ON  stockist.memberid = transactions.memberid 
WHERE trans_type='cp' 
GROUP BY stockistname ORDER BY amount DESC LIMIT 1

你为什么在你的加入中做子查询?你为什么在你的加入中做子查询?快告诉我!此外,您还将子查询移出了连接,什么是不发生?从这个问题中得到了什么?吃我吧!此外,您还将子查询移出了连接,什么是不发生?从这个查询中返回的内容确实有效,但金额不是最新的。不过多亏了你的代码,我才能够得到我想要的答案。谢谢,它确实起了作用,但金额不是最新的。不过多亏了你的代码,我才能够得到我想要的答案。谢谢