如何在cakephp 3中获得最近每小时/每天/每周/每年间隔的总计数之和？

我有一张如下的桌子-

现在，我需要在每小时，每周，每月和每年的总计数报告。它的总和可能为0，但应包含在结果中。例如，我需要如下结果-

$hourlyResult = array(
'00:01' => '5',
'00:02' => '9',
'00:03' => '50',
'00:04' => '5',
..............
..............
'00:55' => '95',
'00:56' => '0',
'00:57' => '20',
'00:58' => '33',
'00:59' => '5',
);

$weeklyResult = array(
'SAT' => '500',
'SUN' => '300'
.............
.............
'FRI' => '700'
);

如何在cakephp 3中构建查询？我得到了下面的链接，但不能走这么远

我所做的-

    $this->loadModel('Searches');   
    $searches = $this->Searches
        ->find('all')
        ->select(['created', 'count'])
        ->where('DATE(Searches.created) = DATE_SUB(CURDATE(), INTERVAL 1 DAY)')
        ->group(WEEK(date))
        ->hydrate(false)
        ->toArray();
    pr($searches);

---

这是你可以做到的

按年度求和

    $query = $this->Searches->find();
    $query = $this->Searches
        ->find()
        ->select([
            'total_count' => $query->func()->sum('count'),
            'year' => $query->func()->year(['created' => 'literal'])
        ])
        ->group(['year'])
        ->hydrate(false);

    $query = $this->Searches
        ->find()
        ->select(['total_count' => 'SUM(count)', 'year' => 'YEAR(created)'])
        ->group(['year'])
        ->hydrate(false);

    $query = $this->Searches
        ->find()
        ->select(['total_count' => 'SUM(count)', 'day_of_week' => 'DAYOFWEEK(created)'])
        ->group(['day_of_week'])
        ->hydrate(false);

或

    $query = $this->Searches->find();
    $query = $this->Searches
        ->find()
        ->select([
            'total_count' => $query->func()->sum('count'),
            'year' => $query->func()->year(['created' => 'literal'])
        ])
        ->group(['year'])
        ->hydrate(false);

    $query = $this->Searches
        ->find()
        ->select(['total_count' => 'SUM(count)', 'year' => 'YEAR(created)'])
        ->group(['year'])
        ->hydrate(false);

    $query = $this->Searches
        ->find()
        ->select(['total_count' => 'SUM(count)', 'day_of_week' => 'DAYOFWEEK(created)'])
        ->group(['day_of_week'])
        ->hydrate(false);

按星期几求和

    $query = $this->Searches->find();
    $query = $this->Searches
        ->find()
        ->select([
            'total_count' => $query->func()->sum('count'),
            'day_of_week' => $query->func()->dayOfWeek('created')
        ])
        ->group(['day_of_week'])
        ->hydrate(false);

或

    $query = $this->Searches->find();
    $query = $this->Searches
        ->find()
        ->select([
            'total_count' => $query->func()->sum('count'),
            'year' => $query->func()->year(['created' => 'literal'])
        ])
        ->group(['year'])
        ->hydrate(false);

    $query = $this->Searches
        ->find()
        ->select(['total_count' => 'SUM(count)', 'year' => 'YEAR(created)'])
        ->group(['year'])
        ->hydrate(false);

    $query = $this->Searches
        ->find()
        ->select(['total_count' => 'SUM(count)', 'day_of_week' => 'DAYOFWEEK(created)'])
        ->group(['day_of_week'])
        ->hydrate(false);

同样的方法，你可以得到总金额按小时或月。

---

在这里您可以阅读和。

Raw

query可以吗？我想知道cakephp的方法。不过，我也不知道原始查询。好的。然后你必须等到一个

蛋糕php

的家伙过来。如果你不介意，请告诉我原始查询方式，因为cakephp也支持原始查询。如果我没有找到任何cakephp的家伙，那么我将以原始方式实现。然后我需要更多信息：您的预期输出是什么样的？你所说的每周是指一周/最后7天吗？事实上，您的预期输出将回答许多问题。