Php 我试图把标题，但它完全

您可能需要使用，即：

---

如果您只需要第一个标题，可以使用：

$url = "https://www.ethnews.com/rss.xml";
$feed = simplexml_load_file($url);

foreach($feed->channel->item as $story) {
    echo $story->title;
    # other options :
    # echo $story->desc;
    # echo $story->link;
    # echo $story->date;
}

---

对不起标题…我试图回应这个rss提要，但它完全是什么？

$url = "https://www.ethnews.com/rss.xml";
$feed = simplexml_load_file($url);

foreach($feed->channel->item as $story) {
    echo $story->title;
    # other options :
    # echo $story->desc;
    # echo $story->link;
    # echo $story->date;
}

$url = "https://www.ethnews.com/rss.xml";
$feed = simplexml_load_file($url);
echo $feed->channel->item[0]->title;