Php 在此代码中如何使用LIKE运算符？

这是我的搜索引擎php代码。数据库中有三个字段：标题、描述和Url。但它将只显示与标题匹配的搜索查询。如何创建与标题、描述和Url匹配的搜索查询

<?php

ini_set('display_errors',0); // turn off php notice  & errors


$button = $_GET ['submit'];
$search = $_GET ['search'];

if(strlen($search)<=1)
echo "Search term too short";
else{
echo "You searched for <b>$search</b> <hr size='1'></br>";
mysql_connect("localhost","woogle","woogle");
mysql_select_db("search");                  

$search_exploded = explode (" ", $search);

foreach($search_exploded as $search_each)
{
$x++;
if($x==1)
$construct .="title LIKE '%$search_each%'";
else
$construct .="AND title LIKE '%$search_each%'";
}


$constructs ="SELECT * FROM searchengine WHERE $construct";

$run = mysql_query($constructs);

$foundnum = mysql_num_rows($run);

if ($foundnum==0)
echo "Sorry, there are no matching result for <b>$search</b>";
else
{
echo "$foundnum results found !<p>";
}

试试这个：

foreach($search_exploded as $search_each)
{
    $x++;
    $search_each_e = mysql_real_escape_string($search_each);    // To help prevent SQL injection
    if($x==1)
        $construct .="(title LIKE '%$search_each_e%' OR description LIKE '%$search_each_e%' OR url LIKE '%$search_each_e%')";
    else
        $construct .="AND (title LIKE '%$search_each_e%' OR description LIKE '%$search_each_e%' OR url LIKE '%$search_each_e%')";
}

。但是，我认为使用是一种更稳健的方法。
尝试以下方法：

 $construct = " 1 " 

 foreach($search_exploded as $search_each)
 {
   $construct .=" AND (title LIKE '%$search_each%' OR description LIKE '%$search_each%' OR url LIKE '%$search_each%')";
 }

哇，仅仅是我还是被利用的时机已经成熟了？有一点是，它看起来不像是你在
描述
或
url
中进行查询搜索。现在我只看到搜索
标题
Woogle的代码……这很有趣。如果你不想使用参数，你至少应该使用你应该继续阅读的代码，因为你的脚本很容易受到它的攻击。