Php-将时间段划分为相等的间隔

Php-将时间段划分为相等的间隔,php,time,intervals,Php,Time,Intervals,我必须创建一个函数,该函数获取5个表示某个部门工作时间信息的参数。 -工作开始/结束时, -午餐时间(或任何其他休息时间)开始/结束时, -整数,表示将分钟划分为时间段的大小 此外,工作时间内可能没有休息时间 function split_time_into_intervals($work_starts,$work_ends,$break_starts=null; $break_ends=null,$minutes_per_interval=60) { $interv

我必须创建一个函数,该函数获取5个表示某个部门工作时间信息的参数。
-工作开始/结束时,
-午餐时间(或任何其他休息时间)开始/结束时,
-整数,表示将分钟划分为时间段的大小

此外,工作时间内可能没有休息时间

function split_time_into_intervals($work_starts,$work_ends,$break_starts=null;
          $break_ends=null,$minutes_per_interval=60)
{
    $intervals=array();

    //all of the function code
    return $intervals;
}
该函数应返回工作时间的所有间隔

function split_time_into_intervals($work_starts,$work_ends,$break_starts=null;
          $break_ends=null,$minutes_per_interval=60)
{
    $intervals=array();

    //all of the function code
    return $intervals;
}
如果我有以下函数参数

function split_time_into_intervals("8:30","14:50","11:45", "12:25");
我想检索以下数组:

$intervals[0]['starts']="8:30";
$intervals[0]['ends']="9:30";
$intervals[1]['starts']="9:30";
$intervals[1]['ends']="10:30";
$intervals[2]['starts']="10:30";
$intervals[2]['ends']="11:30";
$intervals[3]['starts']="11:30";
$intervals[3]['ends']="11:45";

//this interval was smaller than 60 minutes - because of the break (which starts at 11:45)
$intervals[4]['starts']="12:25";//starts when the break ends
$intervals[4]['ends']="13:25"; // interval is again 60 minutes
$intervals[5]['starts']="13:25";
$intervals[5]['ends']="14:25";
$intervals[6]['starts']="14:25";
$intervals[6]['ends']="14:50";

//this period is shorter than 60 minutes - because work ends 

有什么建议吗?关于这个问题,我会解释任何php(或C#)代码

好吧,这可能有点无效,但您可以尝试一下(我没有测试它,它可能有一些错误,但它应该能起到类似的作用:

$time = $work_starts;

while($time < $work_ends)
{
     if( ($break_starts !== null) && ($time + 60 <= $break_starts) )
     {
         $intervals[] = array( 'starts' => $time, 'ends' => ($time += 60) );
     }
     else if( $break_starts !== null ) 
     {
         $time = $break_ends;
     }
     else if( $time + 60 <= $work_ends )
     {
         $intervals[] = array( 'starts' => $time, 'ends' => ($time += 60) );
     }
 }
$time=$work\u开始;
而($time<$work\u结束)
{
如果($break_start!==null)&($time+60$time,'ends'=>($time+=60));
}
else if($break_start!==null)
{
$time=$break\u结束;
}
否则如果($time+60$time,'ends'=>($time+=60));
}
}
当然,
$time+=60
应该转换为实际的分钟加法。这是一个伪算法


希望它能帮助我最终解决我的问题!谢谢tharkun的关注! 现在它可以正常工作了!我想在某些情况下,这个函数可能会出现一些bug,所以我想知道它们是否会出现。 现在这里有两个函数。抱歉,如果它可以写得更短、更优化,但至少它可以工作

//Author: Elvijs Kukša
function splitTimeIntoIntervals($work_starts,$work_ends,$break_starts=null,$break_ends=null,$minutes_per_interval=60){
$intervals=array();
$time = date("H:i",strtotime($work_starts));
$first_after_break=false;
while( strtotime($time) < strtotime($work_ends)){
// if at least one of the arguments associated with breaks is mising - act like there is no break
    if($break_starts==null || $break_starts==null )
    {
    $time_starts=date("H:i", strtotime($time));
    $time_ends=date("H:i", strtotime($time_starts."+$minutes_per_interval minutes"));
    }
// if the break start/end time is specified
    else{
    if($first_after_break==true){//first start time after break
    $time=(date("H:i",strtotime($break_ends)));
    $first_after_break=false;
    }
    $time_starts=(date("H:i",strtotime($time)));
    $time_ends=date("H:i", strtotime($time_starts."+$minutes_per_interval minutes"));
//if end_time intersects break_start and break_end times
    if(timesIntersects($time_starts, $time_ends, $break_starts, $break_ends))
    {
    $time_ends=date("H:i",strtotime($break_starts));
    $first_after_break=true;
    }
    }
    //if end_time is after work_ends
    if(date("H:i", strtotime($time_ends))>date("H:i",strtotime($work_ends)))
    {
    $time_ends=date("H:i",strtotime($work_ends));
    }
    $intervals[] = array( 'starts' =>$time_starts, 'ends' => $time_ends);
    $time=$time_ends;
}
return $intervals;
}
//time intersects if order of parametrs is one of the following 1342 or 1324


function timesIntersects($time1_from,$time1_till, $time2_from, $time2_till){
    $out;
    $time1_st=strtotime($time1_from);
    $time1_end=strtotime($time1_till);
    $time2_st=strtotime($time2_from);
    $time2_end=strtotime($time2_till);
    $duration1 =$time1_end - $time1_st;
    $duration2 = $time2_end - $time2_st;
    $time1_length=date("i",strtotime($time1_till."-$time1_from"));
    if(
            (($time1_st<=$time2_st&&$time2_st<=$time1_end&&$time1_end<=$time2_end)
            ||
            ($time1_st<=$time2_st&&$time2_st<=$time2_end&&$time2_end<=$time1_end)
            &&
            ($duration1>=$duration2)
            )
            ||
            ( $time1_st<=$time2_st&&$time2_st<=$time1_end&&$time1_end<=$time2_end)
            &&
            ($duration1<$duration2)
            )
    {
        return true;
    }


    return false;
}
//作者:Elvijs Kukša
函数将时间分割为间隔($work\u start,$work\u ends,$break\u start=null,$break\u ends=null,$minutes\u per\u interval=60){
$interval=array();
$time=日期(“H:i”,strottime($work_start));
$first_在_中断后=false;
while(strotime($time)日期(“H:i”,strotime($work_结束)))
{
$time_ends=日期(“H:i”,strottime($work_ends));
}
$interval[]=数组('start'=>$time\u start,'ends'=>$time\u ends);
$time=$time\u结束;
}
返回$interval;
}
//如果参数的顺序为以下1342或1324之一,则时间相交
函数timesIntersects($time1\u from,$time1\u till,$time2\u from,$time2\u till){
$out;
$time1\u st=strotime($time1\u from);
$time1\u end=strotime($time1\u-till);
$time2\u st=strotime($time2\u from);
$time2\u end=strotime($time2\u-till);
$duration1=$time1\u end-$time1\u st;
$duration2=$time2\u end-$time2\u st;
$time1_length=日期(“i”,strottime($time1_-till.-$time1_-from”);
如果(

($time1_stu这是家庭作业吗?它不是一个常规的家庭作业-它只是我php项目中的一个函数-整个项目都是我的“家庭作业”(实际上是课程论文)