Php 在现有阵列内创建另一个关联阵列

我试图在数组中创建一个数组，以便将其编码为JSON。我希望我的数组如下所示：

<pre>Array
(
    [user] => John Smith
              Array
        (
            [profile] => 
            [podcast] => Array
                (
                    [0] => stdClass Object
                        (
                            [id] => 4
                            [title] => How to display array inside array?
                            [description] => Unexpected array being displayed!
                            [category] => 1
                            [duration] => 0:05:05
                            [audio] => http://demo.web/uploads/podAudio/PodAudio-20190114102432822.mp3
                            [image] => http://demo.web/uploads/podImage/PodImage-20190114102432145.jpg
                            [added_by] => 1
                            [updated_date] => 
                        )

                )

        )

)
</pre>

数组
(
[用户]=>约翰·史密斯
排列
(
[个人资料]=>
[podcast]=>阵列
(
[0]=>stdClass对象
(
[id]=>4
[标题]=>如何在阵列中显示阵列？
[说明]=>正在显示意外数组！
[类别]=>1
[持续时间]=>0:05:05
[音频]=>http://demo.web/uploads/podAudio/PodAudio-20190114102432822.mp3
[图片]=>http://demo.web/uploads/podImage/PodImage-20190114102432145.jpg
[添加人]=>1
[更新日期]=>
)
)
)
)

以下是我获取阵列的代码：

    <pre>Array
           (
    [user] => Array
        (
            [name] => Lenna Smith
            [profile] => 
            [podcast] => Array
                (
                    [0] => stdClass Object
                        (
                            [id] => 4
                            [title] => How to display array inside array?
                            [description] => Unexpected array being displayed!
                            [category] => 1
                            [duration] => 0:05:05
                            [audio] => http://demo.web/uploads/podAudio/PodAudio-20190114102432822.mp3
                            [image] => http://demo.web/uploads/podImage/PodImage-20190114102432145.jpg
                            [added_by] => 1
                            [updated_date] => 
                        )

                )

        )

)
</pre>

但是，上面的代码为我提供了一个如下所示的数组：

数组
(
[用户]=>阵列
(
[姓名]=>Lenna Smith
[个人资料]=>
[podcast]=>阵列
(
[0]=>stdClass对象
(
[id]=>4
[标题]=>如何在阵列中显示阵列？
[说明]=>正在显示意外数组！
[类别]=>1
[持续时间]=>0:05:05
[音频]=>http://demo.web/uploads/podAudio/PodAudio-20190114102432822.mp3
[图片]=>http://demo.web/uploads/podImage/PodImage-20190114102432145.jpg
[添加人]=>1
[更新日期]=>
)
)
)
)

---

是否有任何代码需要替换或添加，以便获得所需的数组？如有任何建议，将不胜感激

简单地做以下更改对我有帮助

您的期望输出没有意义-您不能将

[user]=>John Smith

作为数组。也许你想用“约翰·史密斯”作为键？这是PHP吗？请始终将语言（和可能的框架）作为标记。我是否必须更改代码以获得所需的输出？如果是这样的话，我需要添加什么以及在哪里？您不能更改为代码以获得该输出，因为您希望的输出具有语法error@DavidWinder，是否可以将“John Smith”设置为键，并在其中具有键和值的关联数组？

    <pre>Array
           (
    [user] => Array
        (
            [name] => Lenna Smith
            [profile] => 
            [podcast] => Array
                (
                    [0] => stdClass Object
                        (
                            [id] => 4
                            [title] => How to display array inside array?
                            [description] => Unexpected array being displayed!
                            [category] => 1
                            [duration] => 0:05:05
                            [audio] => http://demo.web/uploads/podAudio/PodAudio-20190114102432822.mp3
                            [image] => http://demo.web/uploads/podImage/PodImage-20190114102432145.jpg
                            [added_by] => 1
                            [updated_date] => 
                        )

                )

        )

)
</pre>

<?php 
    $userList = $user->getAllUserName();

    foreach ($userList as $users) { 
        $fullname = $users->full_name;
        $profile = $users->image;
        $id = $users->id;

        $podcastList = $podcast->getUserPodcast($id);

        if (!empty($podcastList)) {
            $output[$fullname] = array(
            'profile'   => $profile,
            'podcast' => $podcastList
        );
        }

    }    

    $json = array(
        'user'  => $output
    );   
     echo "<pre>";
    print_r($json);
    echo "</pre>";
    ?>