Php 通过比较另一个数组的键从一个数组中删除数组值
假设我有第一个数组,$aAllCities作为Php 通过比较另一个数组的键从一个数组中删除数组值,php,arrays,Php,Arrays,假设我有第一个数组,$aAllCities作为 Array ( [21] => London [9] => Paris [17] => New York [3] => Tokyo [25] => Shanghai [11] => Dubai [37] => Mumbai ) 和另一个数组,$ANOTSUPPORTDCITIES作为 Array ( [0] => 37 [1] => 2
Array
(
[21] => London
[9] => Paris
[17] => New York
[3] => Tokyo
[25] => Shanghai
[11] => Dubai
[37] => Mumbai
)
和另一个数组,$ANOTSUPPORTDCITIES作为
Array
(
[0] => 37
[1] => 25
[2] => 11
)
有可能得到这样的数组吗
Array
(
[21] => London
[9] => Paris
[17] => New York
[3] => Tokyo
)
我想删除其他数组中存在的键的数组值,请尝试以下操作:
$new = $aAllCities;
foreach($aNotSupportedCities as $id) {
if (isset($new[$id]) {
unset($new[$id]);
}
}
$aAllCities = array_flip( $aAllCities );
$aAllCities = array_diff( $aAllCities, $aNotSupportedCities );
$aAllCities = array_flip( $aAllCities );
希望这有帮助。试试这个:
$aAllCities = array_flip( $aAllCities );
$aAllCities = array_diff( $aAllCities, $aNotSupportedCities );
$aAllCities = array_flip( $aAllCities );
希望这能有所帮助。其他答案都是正确的,但更流畅、更快的方法是:
$supportedCities=array_diff_key($aAllCities,$aNotSupportedCities)代码>
这将返回$aAllCities
中没有键的所有值
请注意,这将通过两个数组的键来比较它们,因此您需要将$anotsupportdcities
设置为如下所示:
Array
(
[37] => something
[25] => doesn't really matter
[11] => It's not reading this
)
祝你好运。其他答案都是正确的,但更流畅、更快的方法是:
$supportedCities=array_diff_key($aAllCities,$aNotSupportedCities)代码>
这将返回$aAllCities
中没有键的所有值
请注意,这将通过两个数组的键来比较它们,因此您需要将$anotsupportdcities
设置为如下所示:
Array
(
[37] => something
[25] => doesn't really matter
[11] => It's not reading this
)
祝你好运。谢谢普什佩斯,正是我想要的谢谢普什佩斯,正是我想要的