在php中,我应该如何获得这样的数组?

在php中,我应该如何获得这样的数组?,php,arrays,multidimensional-array,foreach,Php,Arrays,Multidimensional Array,Foreach,我有一个数组,如下所示: Array ( [Sep] => Array ( [Support Help Desk] => 24.67 [Development] => 7.74 [Consulting Services] => 4.04 ) [Oct] => Array ( [Support Help Desk] => 14.38 [Business A

我有一个数组,如下所示:

Array
(
 [Sep] => Array
    (
        [Support Help Desk] => 24.67
        [Development] => 7.74
        [Consulting Services] => 4.04
    )

[Oct] => Array
    (
        [Support Help Desk] => 14.38
        [Business Activity] => 1.92
        [Maintenance Tasks] => 1.00
        [Development] => 2.11
    )

)
我想要这样的数组:

   Array
    (
        [Support Help Desk] => 24.67,14.38
        [Development] => 7.74,2.11           
        [Consulting Services] => 4.04,0
        [Business Activity] => 0,1.92
        [Maintenance Tasks] => 0,1.00
    )    
我正在使用带有zend框架的php。 但我不知道应该使用什么方法来获得这样的数组

谁能给我指路吗

-


提前感谢。

第三次幸运!我本来错过了问题中的一些微妙之处。试试下面的代码——虽然有点不太清楚,但它应该适合你

我假设您的原始数组名为
$data

// first we need to 'normalise' or fill in the blanks in the contents of the sub array
// get a unique list of all the keys shared - doing it manually here

$keys = ['Support Help Desk', 'Business Activity', 'Maintenance Tasks', 'Development', 'Consulting Services'];

// create a default array with $keys, assigning 0 as the value of each

$default = array_fill_keys($keys, 0);

// next fill in the blanks...
// get the diff (missing keys) between the current element and the default array
// merge the missing key/value pairs

array_walk($data, function(&$month, $key, $default) {
    $diff = array_diff_key($default, $month);
    $month = array_merge($diff, $month);
}, $default);


// now the array is normalised
// flatten the array... where there are duplicate values for a key, and
// there will be in all cases now including default values
// a sub array is created

$merged = call_user_func_array('array_merge_recursive', $data);

// finally loop over the merged array
// and implode each array of values into a comma separated list

foreach ($merged as &$element) {
    if (is_array($element)) {
        $element = implode(', ', $element);
    }
}

// done :)

var_dump($merged);
收益率:

array (size=5)
  'Business Activity' => string '0, 1.92' (length=7)
  'Maintenance Tasks' => string '0, 1' (length=4)
  'Support Help Desk' => string '24.67, 14.38' (length=12)
  'Development' => string '7.74, 2.11' (length=10)
  'Consulting Services' => &string '4.04, 0' (length=7)
希望这有帮助:)

编辑


如果每个月您可能有不同的密钥,但您事先不知道所有密钥,您可以使用下面的代码($month\u数组是您的预处理数组)


假设您的数组存储在
$main\u arr
中,结果数组是
$result\u arr

$result_arr = array();

foreach ($main_arr as $month) {
    foreach ($month as $key => $val) {
        if (!isset($result_arr[$key])) {
            $result_arr[$key] = array($val);
        } else {
            array_push($result_arr[$key], $val);
        }
    } 
}

foreach ($result_arr as $key => $val) {
    $result_arr[$key] = implode(', ',  $val);
}

print_r($result_arr); //Final output. 

谢谢你,达拉格。。它起作用了。我将分别获取密钥,而不是使用您的方法。非常感谢…没问题@Mausami-很高兴能帮忙!
$result_arr = array();

foreach ($main_arr as $month) {
    foreach ($month as $key => $val) {
        if (!isset($result_arr[$key])) {
            $result_arr[$key] = array($val);
        } else {
            array_push($result_arr[$key], $val);
        }
    } 
}

foreach ($result_arr as $key => $val) {
    $result_arr[$key] = implode(', ',  $val);
}

print_r($result_arr); //Final output.