谷歌地图API-使用PHP检索城市和州
我目前正在使用谷歌地图API从用户的街道、街道号码和邮政编码中获取经度和纬度 我还想从地图API结果中获取他们的城市和州。尽管XML文档的格式很奇怪,但我不确定应该如何引用它(这与我获取long和lat的方式不同) 以下是我加载地图API的方式:谷歌地图API-使用PHP检索城市和州,php,google-maps,rest,google-maps-api-3,Php,Google Maps,Rest,Google Maps Api 3,我目前正在使用谷歌地图API从用户的街道、街道号码和邮政编码中获取经度和纬度 我还想从地图API结果中获取他们的城市和州。尽管XML文档的格式很奇怪,但我不确定应该如何引用它(这与我获取long和lat的方式不同) 以下是我加载地图API的方式: $map_address = str_replace($address."+".$zip); $map_api_url = "https://maps.googleapis.com/maps/api/geocode/json?address=".$ma
$map_address = str_replace($address."+".$zip);
$map_api_url = "https://maps.googleapis.com/maps/api/geocode/json?address=".$map_address."&key=myKey";
$resp_json = file_get_contents($map_api_url);
$resp = json_decode($resp_json, true);
然后我得到了长和宽:
$lati = $resp['results'][0]['geometry']['location']['lat'];
$longi = $resp['results'][0]['geometry']['location']['lng'];
但我如何抓住城市和国家
{
"results" : [
{
"address_components" : [
{
"long_name" : "3840",
"short_name" : "3840",
"types" : [ "street_number" ]
},
{
"long_name" : "Fake Street",
"short_name" : "Fake St",
"types" : [ "route" ]
},
{
"long_name" : "Wilson Heights",
"short_name" : "Wilson Heights",
"types" : [ "neighborhood", "political" ]
},
{
"long_name" : "North York",
"short_name" : "North York",
"types" : [ "sublocality_level_1", "sublocality", "political" ]
},
{
"long_name" : "Toronto",
"short_name" : "Toronto",
"types" : [ "locality", "political" ]
},
{
"long_name" : "Toronto Division",
"short_name" : "Toronto Division",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "Ontario",
"short_name" : "ON",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "Canada",
"short_name" : "CA",
"types" : [ "country", "political" ]
},
{
"long_name" : "M6H",
"short_name" : "M6H",
"types" : [ "postal_code_prefix", "postal_code" ]
}
],
"formatted_address" : "3840 Fake Street, Toronto, ON M6H, Canada",
"geometry" : {
"location" : {
"lat" : 43.5399244,
"lng" : -78.43486559999999
},
"location_type" : "ROOFTOP",
"viewport" : {
"northeast" : {
"lat" : 43.5412733802915,
"lng" : -78.43351661970848
},
"southwest" : {
"lat" : 43.7385754197085,
"lng" : -79.43621458029151
}
}
},
"place_id" : "ChIJPVDxjGgyK4gRt3O7zOSmIF4",
"types" : [ "street_address" ]
}
],
"status" : "OK"
}
刚才通过循环运行代码回答了我自己的问题。如果你有更好的方法,请告诉我
foreach($resp['results'][0]['address_components'] as $address_componenets) {
if($address_componenets["types"][0]=="country") {
$country = $address_componenets["long_name"];
}
if($address_componenets["types"][0]=="administrative_area_level_1") {
$state = $address_componenets["long_name"];
}
if($address_componenets["types"][0]=="locality") {
$city = $address_componenets["long_name"];
}
}