plsql-在UPDATE-SET中使用平均最大值函数
我想更新另两列作为条件分组的列的值。假设表A A Char,b integer,c integer,d和A列可以包含相同的对象名,所以我想用以下条件更新表:如果列的A值和b值在两行row1:A1,2,numbery和row2:A1,2,numberx中找到,那么if:numberx,numbery>=0->AVGthird column,elsif numberx,numbery10plsql-在UPDATE-SET中使用平均最大值函数,plsql,Plsql,我想更新另两列作为条件分组的列的值。假设表A A Char,b integer,c integer,d和A列可以包含相同的对象名,所以我想用以下条件更新表:如果列的A值和b值在两行row1:A1,2,numbery和row2:A1,2,numberx中找到,那么if:numberx,numbery>=0->AVGthird column,elsif numberx,numbery10 创建表和示例数据: SQL> create table t (a varchar2(20) not nul
创建表和示例数据:
SQL> create table t (a varchar2(20) not null
2 , b number(38) not null
3 , c number(38) not null
4 , d varchar2(20) not null);
Table created.
SQL> insert into t values ('A1', 2, 10, 'b');
1 row created.
SQL> insert into t values ('A2', 7, -9, 'bc');
1 row created.
SQL> insert into t values ('A3', 7, 12, 'fg');
1 row created.
SQL> insert into t values ('A1', 2, 20, 'sa');
1 row created.
SQL> insert into t values ('A2', 7, 4, 'sa');
1 row created.
SQL> commit;
Commit complete.
为了帮助理解更新,创建一个查询,根据我的理解提供所需的结果:不是解决方案的一部分,只是解决方案的一部分
SQL> select t.a, t.b
2 , case when agg_t.min_c >= 0 then avg_c -- all values of c are >= 0
3 when agg_t.max_c < 0 then min_c -- all values of c are < 0
4 else agg_t.max_c end as c
5 , t.d
6 from (select a, b, min(c) as min_c
7 , max(c) as max_c , avg(c) as avg_c
8 from t
9 group by a, b) agg_t
10 inner join t on agg_t.a = t.a and agg_t.b = t.b
11 /
A B C D
-------------------- ---------- ---------- --------------------
A3 7 12 fg
A1 2 15 sa
A2 7 4 bc
A2 7 4 sa
A1 2 15 b
回滚到初始测试数据:
SQL> rollback;
Rollback complete.
此查询不会更新实际未进行更改的行,从而减少锁定、撤消和重做:
SQL> merge into T dest
2 using (select a, b
3 , case when min_c >= 0 then avg_c -- all values of c are >= 0
4 when max_c < 0 then min_c -- all values of c are < 0
5 else max_c end as new_c
6 from (select a, b, min(c) as min_c
7 , max(c) as max_c , avg(c) as avg_c
8 from t
9 group by a, b)) src
10 on (dest.a = src.a and dest.b = src.b)
11 when matched then update set c = new_c
12 where c <> new_c
13 or (c is null and new_c is not null)
14 or (c is not null and new_c is null)
15 /
3 rows merged.
SQL>
SQL> select * from t;
A B C D
-------------------- ---------- ---------- --------------------
A1 2 15 b
A2 7 4 bc
A3 7 12 fg
A1 2 15 sa
A2 7 4 sa
请尽量让它更具可读性。那是什么,某种奇怪的代数?
SQL> rollback;
Rollback complete.
SQL> merge into T dest
2 using (select a, b
3 , case when min_c >= 0 then avg_c -- all values of c are >= 0
4 when max_c < 0 then min_c -- all values of c are < 0
5 else max_c end as new_c
6 from (select a, b, min(c) as min_c
7 , max(c) as max_c , avg(c) as avg_c
8 from t
9 group by a, b)) src
10 on (dest.a = src.a and dest.b = src.b)
11 when matched then update set c = new_c
12 where c <> new_c
13 or (c is null and new_c is not null)
14 or (c is not null and new_c is null)
15 /
3 rows merged.
SQL>
SQL> select * from t;
A B C D
-------------------- ---------- ---------- --------------------
A1 2 15 b
A2 7 4 bc
A3 7 12 fg
A1 2 15 sa
A2 7 4 sa