Python 2.7 PyQt4 QTabWidget选项卡更改…currentChange(int)不起作用
我的QTabWidget有一个很大的问题 我有一个小示例程序,当我更改选项卡时,更改选项卡会给我一个带有“current tab index:…”的消息框,这非常好:Python 2.7 PyQt4 QTabWidget选项卡更改…currentChange(int)不起作用,python-2.7,pyqt4,qtabwidget,Python 2.7,Pyqt4,Qtabwidget,我的QTabWidget有一个很大的问题 我有一个小示例程序,当我更改选项卡时,更改选项卡会给我一个带有“current tab index:…”的消息框,这非常好: from PyQt4 import QtGui from PyQt4 import QtCore from PyQt4.QtCore import pyqtSlot,SIGNAL,SLOT import sys class myTabWidget(QtGui.QTabWidget): def tabChangedSlot(
from PyQt4 import QtGui
from PyQt4 import QtCore
from PyQt4.QtCore import pyqtSlot,SIGNAL,SLOT
import sys
class myTabWidget(QtGui.QTabWidget):
def tabChangedSlot(self,argTabIndex):
QtGui.QMessageBox.information(self,"Tab Index Changed!",
"Current Tab Index: "+QtCore.QString.number(argTabIndex));
def main():
app = QtGui.QApplication(sys.argv)
tabWidget = myTabWidget()
tabWidget.addTab(QtGui.QWidget(),"1");
tabWidget.addTab(QtGui.QWidget(),"2");
tabWidget.addTab(QtGui.QWidget(),"3");
#Resize width and height
tabWidget.resize(300,120)
tabWidget.setWindowTitle('QTabWidget Changed Example')
tabWidget.connect(tabWidget,
SIGNAL("currentChanged(int)"),tabWidget,SLOT("tabChangedSlot(int)"))
tabWidget.show()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
“
现在我的问题是:
我用PyQT4中的QT设计器创建了一个GUI,称为“abaqusian”。
QTabWidget称为“Ui_AbaqusianV1()
问题是,我很难发出信号“currentchanged(int)”。更改选项卡时,带有“当前选项卡索引:…”的弹出窗口将不会显示
此外,程序知道tab索引,因为函数调用了tab索引
“ongenoptions_savebutton(self)”的打印完全正确………怎么了
以下是主程序的代码:
from PyQt4 import QtCore
from PyQt4 import QtGui
import sys,os
from PyQt4.QtCore import pyqtSlot,SIGNAL,SLOT
from Tkinter import Tk
from tkFileDialog import askopenfilename
from tkFileDialog import askdirectory
import Tkconstants
class Ui_AbaqusianV1(QtGui.QTabWidget):
def setupUi(self, AbaqusianV1):
AbaqusianV1.setObjectName(_fromUtf8("AbaqusianV1"))
AbaqusianV1.resize(567, 530)
.....
.....
self.retranslateUi(AbaqusianV1)
.....
QtCore.QObject.connect(self.genoptions_savebutton, QtCore.SIGNAL("clicked()"),
self.ongenoptions_savebutton)
......
TableuGenerale=Ui_AbaqusianV1()
QtCore.QObject.connect(TableuGenerale,QtCore
.SIGNAL(_fromUtf8("currentChanged(int)")),
self.tabChangedSlot)
def tabChangedSlot(self,argTabIndex):
QtGui.QMessageBox.information(self,
"Tab Index Changed!",
"Current TabIndex:"+QtCore.QString.number(argTabIndex));
def ongenoptions_savebutton(self):
# Daten auslesen
d = {}
self.TableuGenerale=Ui_AbaqusianV1()
print "\n"
print "*****************************************************************"
print "GENERAL OPTIONS:"
print "\n"
print "Project Name: %s" % self.projectname.text()
print "Save location Abaqusian: %s" % abaqusian_dir
print "Save location Inp. Files: %s" % inpfiles_dir
print "\n"
print "current tab index is: %s" % self.TableuGenerale.currentIndex()
print "GENERAL OPTIONS ----> SAVED"
print "*****************************************************************"
.....
.....
.....
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
AbaqusianV1 = QtGui.QTabWidget()
ui = Ui_AbaqusianV1()
ui.setupUi(AbaqusianV1)
AbaqusianV1.show()
sys.exit(app.exec_())
我只是不知道怎么了。
我的小样本程序运行良好。
我在我的主程序中做完全相同的事情。
Python没有给我任何错误,只是在更改选项卡时没有显示弹出消息窗口。
我无法调试,因为没有导致错误
谢谢你的帮助
问候
A.Neumeir试试这个:
QtCore.QObject.connect(self, QtCore.SIGNAL(_fromUtf8("currentChanged(int)")), self.tabChangedSlot)
而不是这一行:
QtCore.QObject.connect(TableuGenerale, QtCore.SIGNAL(_fromUtf8("currentChanged(int)")), self.tabChangedSlot)