Python 3.x 通过从列表中获取列名，将数据帧的列相乘

我有一个数据框架，其中有分类列和数字列

data = [['A',"India",10,20,30,15,"Cochin"],['B',"India",10,20,30,40,"Chennai"],['C',"India",10,20,30,15,"Chennai"]]
df = pd.DataFrame(data,columns=['Product','Country',"2016 Total","2017 Total","2018 Total","2019 Total","Region"])

Product Country 2016 Total  2017 Total  2018 Total  2019 Total  Region
0   A   India   10           20          30          15         Cochin
1   B   India   10           20          30          40         Chennai
2   C   India   10           20          30          15         Chennai

我知道数值变量列的名称（需要动态捕获）：

您可以使用筛选包含

总计的列（与
列列表的结果类似），然后使用over
axis=1
，然后使用
s.map（）
：

使用条件by和for
尝试以下操作：

df['Negative'] = df[cols_list].T.product().apply(lambda x: x < 0)

Product Country 2016 Total  2017 Total  2018 Total  2019 Total  Region  Negative
    0   A   India   10           20          30          15     Cochin No
    1   B   India   10           20          30          40    Chennai No
    2   C   India   10           20          30          15    Chennai No

df['Negative']=df.filter(like='Total').prod(axis=1).lt(0).map({True:'Yes',False:'No'})
print(df)

  Product Country  2016 Total  2017 Total  2018 Total  2019 Total   Region  \
0       A   India          10          20          30          15   Cochin   
1       B   India          10          20          30          40  Chennai   
2       C   India          10          20          30          15  Chennai   

  Negative  
0       No  
1       No  
2       No 

#solution with f-strings for get cols_list by year arange
cols_list = [f'{x} Total' for x in np.arange(start_year, current_year+1)]
print (cols_list)
['2016 Total', '2017 Total', '2018 Total', '2019 Total']

df['Negative'] = np.where(df[cols_list].prod(axis=1).lt(0), 'Yes', 'No')
print (df)
  Product Country  2016 Total  2017 Total  2018 Total  2019 Total   Region  \
0       A   India          10          20          30          15   Cochin   
1       B   India          10          20          30          40  Chennai   
2       C   India          10          20          30          15  Chennai   

  Negative  
0       No  
1       No  
2       No  

df['Negative'] = df[cols_list].T.product().apply(lambda x: x < 0)

>>> t = df[cols_list].T
>>> t
       0   1   2
2016  10  10  10
2017  20  20  20
2018  30  30  30

>>> p = t.product()
>>> p
0    6000
1    6000
2    6000
dtype: int64

>>> neg = p.apply(lambda x: x < 0)
>>> neg
0    False
1    False
2    False
dtype: bool