Python 使函数为单个元组工作，为元组列表工作

我有一个函数

def series_score(sailor, races_to_discard):
    places = sailor[1]
    for i in range(races_to_discard):
        places.remove(max(places))
    print(places)
    sum_of_places = sum(places)
    print(sum_of_places)

这样修改元组

sailor = ("bob", [2, 4, 1, 1, 2, 5])

list_of_sailors = [('Clare', [3, 1, 1, 2, 1, 1]), ('Bob', [2, 2, 3, 1, 2, 3]), ('Alice', [1, 3, 2, 3, 3, 2]), ('Eva', [4, 5, 4, 4, 5, 5]), ('Dennis', [5, 4, 5, 5, 4, 4])]

for sailor,races in list_of_sailors:
     series_score(sailor, races)

通过删除列表中的最高数字，将其转换为

sailor = ("bob", [2, 4, 1, 1, 2])

我如何调整函数来处理这样的元组列表

sailor = ("bob", [2, 4, 1, 1, 2, 5])

list_of_sailors = [('Clare', [3, 1, 1, 2, 1, 1]), ('Bob', [2, 2, 3, 1, 2, 3]), ('Alice', [1, 3, 2, 3, 3, 2]), ('Eva', [4, 5, 4, 4, 5, 5]), ('Dennis', [5, 4, 5, 5, 4, 4])]

for sailor,races in list_of_sailors:
     series_score(sailor, races)

---

你可以这样做

sailor = ("bob", [2, 4, 1, 1, 2, 5])

list_of_sailors = [('Clare', [3, 1, 1, 2, 1, 1]), ('Bob', [2, 2, 3, 1, 2, 3]), ('Alice', [1, 3, 2, 3, 3, 2]), ('Eva', [4, 5, 4, 4, 5, 5]), ('Dennis', [5, 4, 5, 5, 4, 4])]

for sailor,races in list_of_sailors:
     series_score(sailor, races)

---

只需包含另一个循环。在这里，我取下每个数组中最高的两个数字：

def series_score(sailors, races_to_discard):
    for sailor in sailors:
        places = sailor[1]
        for i in range(races_to_discard):
            places.remove(max(places))
        print(places)
        sum_of_places = sum(places)
        print(sum_of_places)

print(series_score([('Clare', [3, 1, 1, 2, 1, 1]), ('Bob', [2, 2, 3, 1, 2, 3]), ('Alice', [1, 3, 2, 3, 3, 2]), ('Eva', [4, 5, 4, 4, 5, 5]), ('Dennis', [5, 4, 5, 5, 4, 4])], 2))
>>>[1, 1, 1, 1]
   4
   [2, 2, 1, 2]
   7
   [1, 2, 3, 2]
   8
   [4, 4, 4, 5]
   17
   [4, 5, 4, 4]
   17

---

适用于水手列表中的水手：系列评分（水手、比赛、弃置）

？当

Eva

列表中有多个

5

时，该怎么办？您希望全部删除还是仅删除1？可能会将此更改为

def series_分数（从比赛到弃置，*水手）

，因此它仍然适用于单个水手。嗯，在我进行更改时，这似乎不起作用。它仍然索引得分列表的元素，而不是列表本身。这对一个水手来说很有效，但它很难看<代码>系列分数（[['Clare'，[3,1,1,2,1,1]]]，2）