Python 如何通过比较值的范围来合并两个数据帧(或传输值)
在以下数据中:Python 如何通过比较值的范围来合并两个数据帧(或传输值),python,pandas,dataframe,merge,bioinformatics,Python,Pandas,Dataframe,Merge,Bioinformatics,在以下数据中: data01 = contig start end haplotype_block 2 5207 5867 1856 2 155667 155670 2816 2 67910 68022 2 2 68464 68483 3 2 525 775 132 2 118938 119559 1157 data02 = contig start last feature
data01 =
contig start end haplotype_block
2 5207 5867 1856
2 155667 155670 2816
2 67910 68022 2
2 68464 68483 3
2 525 775 132
2 118938 119559 1157
data02 =
contig start last feature gene_id gene_name transcript_id
2 5262 5496 exon scaffold_200003.1 CP5 scaffold_200003.1
2 5579 5750 exon scaffold_200003.1 CP5 scaffold_200003.1
2 5856 6032 exon scaffold_200003.1 CP5 scaffold_200003.1
2 6115 6198 exon scaffold_200003.1 CP5 scaffold_200003.1
2 916 1201 exon scaffold_200001.1 NA scaffold_200001.1
2 614 789 exon scaffold_200001.1 NA scaffold_200001.1
2 171 435 exon scaffold_200001.1 NA scaffold_200001.1
2 2677 2806 exon scaffold_200002.1 NA scaffold_200002.1
2 2899 3125 exon scaffold_200002.1 NA scaffold_200002.1
问题:
- 我想比较这两个数据帧的范围(开始-结束)李>
- 如果范围重叠,我想将
和gene_id
值从data02传输到data01中的新列gene_name
我知道您正在使用python,但使用经典的生物信息学工具
bedtools intersect
,您的问题可能很容易解决:
您的两个输入文件均采用标准BED格式:
Bedtools intersect为您提供了如何确定两个区域之间的交点或重叠的高级逻辑。我相信它也可以直接操作bgzipped输入 你应该在python中使用区间树函数,它们非常高效且内存友好,我尝试了类似的方法,并将其运行到某个问题上,该问题后来得到了解决,但下面是我编写的代码, 您可以在此代码的基础上进行构建
s1=data01.start.values
s1 = data01.start.values
e1 = data01.end.values
s2 = data02.start.values
e2 = data02['last'].values
overlap = (
(s1[:, None] <= s2) & (e1[:, None] >= s2)
) | (
(s1[:, None] <= e2) & (e1[:, None] >= e2)
)
g = data02.gene_id.values
n = data02.gene_name.values
i, j = np.where(overlap)
idx_map = {i_: data01.index[i_] for i_ in pd.unique(i)}
def make_series(m):
s = pd.Series(m[j]).fillna('').groupby(i).agg(','.join)
return s.rename_axis(idx_map).replace('', np.nan)
data01.assign(
gene_id=make_series(g),
gene_name=make_series(n),
)
e1=data01.end.values
s2=data02.start.values
e2=data02['last'].值
重叠=(
(s1[:,无]=s2)
) | (
(s1[:,无]=e2)
)
g=data02.gene\U id.values
n=data02.gene\u name.values
i、 j=np.其中(重叠)
idx_map={i_U1;:data01.index[i_U1;]用于pd.unique(i)}
def make_系列(m):
s=pd.Series(m[j]).fillna(“”).groupby(i).agg(‘,’.join)
返回s.rename_轴(idx_映射)。替换(“”,np.nan)
data01.assign(
gene_id=make_系列(g),
基因名称=制造系列(n),
)
如果您想要比bedtools快得多的东西和/或Python science stack的本地居民想要的东西,请尝试:
我以前用过床上工具。由于
start-end
值的原因,我的数据是bed格式的,但我不确定是否有效,是否能够传输这些值(完全按照我的要求)。我已经使用python、pandas、list、dict有一段时间了,使用这些工具来完成特定的任务感觉更好。标准的生物信息学工具很好(如bwa、vcf文件等),但当它变得过于具体时,这些工具变得非常烦人而不是有用。我只是重新访问了bedtools。出于我的目的,我最好使用python和pandas(else字典)。原因是我所做的是大管道的一部分,而引入bedtools只会让事情变得复杂而不是简单。不过,你可能有其他想法/意见。如果有的话,我将不胜感激。ThanksBedtools是为解决您的问题而开发的,这是生物信息学中的一个常见问题。算法本身可能有些细微差别,特别是如果您希望它高效的话。我建议您在开始重新实现该算法之前先尝试一下。;)唯一对我有用的方法是bedtools intersect
,它将使我丢失data01中的数据,或者bedtools merge
,但我只想更新data01中的列值,而不是合并所有信息。我不确定。我打算花些时间在bedtools
上,否则,如果它不起作用,我在python的利基中就太舒服了。哈哈。我不会担心来自bedtools merge
的额外列。床上工具会很快。您可以将结果加载到pandas中,然后向下选择感兴趣的列。谢谢,我会研究它。我不知道目标是什么。如果你能说出你的输出是什么样子的,我很乐意再看一眼。@piRSquared:刚刚添加了所需的输出。我希望这是有道理的。解决这个问题的更好方法是先在两个数据帧上进行conting和start排序(以防止大量for循环),我已经这样做了;但不在上述数据01和数据02中。
contig start end haplotype_block gene_id gene_name
2 5207 5867 1856 scaffold_200003.1,scaffold_200003.1,scaffold_200003.1 CP5,CP5,CP5
# the gene_id and gene_name are repeated 3 times because three intervals (i.e 5262-5496, 5579-5750, 5856-6032) from data02 overlap(or touch) the interval ranges from data01 (5207-5867)
# So, whenever there is overlap of the ranges between two dataframe, copy the gene_id and gene_name.
# and simply NA on gene_id and gene_name for non overlapping ranges
2 155667 155670 2816 NA NA
2 67910 68022 2 NA NA
2 68464 68483 3 NA NA
2 525 775 132 scaffold_200001.1 NA
2 118938 119559 1157 NA NA
s1 = data01.start.values
e1 = data01.end.values
s2 = data02.start.values
e2 = data02['last'].values
overlap = (
(s1[:, None] <= s2) & (e1[:, None] >= s2)
) | (
(s1[:, None] <= e2) & (e1[:, None] >= e2)
)
g = data02.gene_id.values
n = data02.gene_name.values
i, j = np.where(overlap)
idx_map = {i_: data01.index[i_] for i_ in pd.unique(i)}
def make_series(m):
s = pd.Series(m[j]).fillna('').groupby(i).agg(','.join)
return s.rename_axis(idx_map).replace('', np.nan)
data01.assign(
gene_id=make_series(g),
gene_name=make_series(n),
)
import pyranges as pr
c1 = """Chromosome Start End haplotype_block
2 5207 5867 1856
2 155667 155670 2816
2 67910 68022 2
2 68464 68483 3
2 525 775 132
2 118938 119559 1157"""
c2 = """Chromosome Start End feature gene_id gene_name transcript_id
2 5262 5496 exon scaffold_200003.1 CP5 scaffold_200003.1
2 5579 5750 exon scaffold_200003.1 CP5 scaffold_200003.1
2 5856 6032 exon scaffold_200003.1 CP5 scaffold_200003.1
2 6115 6198 exon scaffold_200003.1 CP5 scaffold_200003.1
2 916 1201 exon scaffold_200001.1 NA scaffold_200001.1
2 614 789 exon scaffold_200001.1 NA scaffold_200001.1
2 171 435 exon scaffold_200001.1 NA scaffold_200001.1
2 2677 2806 exon scaffold_200002.1 NA scaffold_200002.1
2 2899 3125 exon scaffold_200002.1 NA scaffold_200002.1"""
gr1, gr2 = pr.from_string(c1), pr.from_string(c2)
j = gr1.join(gr2).sort()
print(j)
# +--------------+-----------+-----------+-------------------+-----------+-----------+------------+-------------------+-------------+-------------------+
# | Chromosome | Start | End | haplotype_block | Start_b | End_b | feature | gene_id | gene_name | transcript_id |
# | (category) | (int32) | (int32) | (int64) | (int32) | (int32) | (object) | (object) | (object) | (object) |
# |--------------+-----------+-----------+-------------------+-----------+-----------+------------+-------------------+-------------+-------------------|
# | 2 | 525 | 775 | 132 | 614 | 789 | exon | scaffold_200001.1 | nan | scaffold_200001.1 |
# | 2 | 5207 | 5867 | 1856 | 5262 | 5496 | exon | scaffold_200003.1 | CP5 | scaffold_200003.1 |
# | 2 | 5207 | 5867 | 1856 | 5579 | 5750 | exon | scaffold_200003.1 | CP5 | scaffold_200003.1 |
# | 2 | 5207 | 5867 | 1856 | 5856 | 6032 | exon | scaffold_200003.1 | CP5 | scaffold_200003.1 |
# +--------------+-----------+-----------+-------------------+-----------+-----------+------------+-------------------+-------------+-------------------+
# Unstranded PyRanges object has 4 rows and 10 columns from 1 chromosomes.
# For printing, the PyRanges was sorted on Chromosome.
print(j.df)
# Chromosome Start End haplotype_block Start_b End_b feature gene_id gene_name transcript_id
# 0 2 525 775 132 614 789 exon scaffold_200001.1 NaN scaffold_200001.1
# 1 2 5207 5867 1856 5262 5496 exon scaffold_200003.1 CP5 scaffold_200003.1
# 2 2 5207 5867 1856 5579 5750 exon scaffold_200003.1 CP5 scaffold_200003.1
# 3 2 5207 5867 1856 5856 6032 exon scaffold_200003.1 CP5 scaffold_200003.1