Python &引用;不是类型标识符“;Cython中的错误
我是Cython的新手,我正在尝试让一个从Python调用C函数的测试项目工作: 测试.cpp:Python &引用;不是类型标识符“;Cython中的错误,python,cython,Python,Cython,我是Cython的新手,我正在尝试让一个从Python调用C函数的测试项目工作: 测试.cpp: void testFn(int arr[]); void testFn(int arr[]) { arr[0] = 1; arr[1] = 2; } cdef extern from "test.cpp": void testFn(int arr[]) cpdef myTest(*arr): testFn(arr) from distutils.core i
void testFn(int arr[]);
void testFn(int arr[])
{
arr[0] = 1;
arr[1] = 2;
}
cdef extern from "test.cpp":
void testFn(int arr[])
cpdef myTest(*arr):
testFn(arr)
from distutils.core import setup
from distutils.extension import Extension
from Cython.Distutils import build_ext
sourcefiles = ['caller.pyx']
ext_modules = [Extension("caller", sourcefiles)]
setup(
name = 'test app',
cmdclass = {'build_ext': build_ext},
ext_modules = ext_modules
)
调用方.pyx:
void testFn(int arr[]);
void testFn(int arr[])
{
arr[0] = 1;
arr[1] = 2;
}
cdef extern from "test.cpp":
void testFn(int arr[])
cpdef myTest(*arr):
testFn(arr)
from distutils.core import setup
from distutils.extension import Extension
from Cython.Distutils import build_ext
sourcefiles = ['caller.pyx']
ext_modules = [Extension("caller", sourcefiles)]
setup(
name = 'test app',
cmdclass = {'build_ext': build_ext},
ext_modules = ext_modules
)
setup.caller.py:
void testFn(int arr[]);
void testFn(int arr[])
{
arr[0] = 1;
arr[1] = 2;
}
cdef extern from "test.cpp":
void testFn(int arr[])
cpdef myTest(*arr):
testFn(arr)
from distutils.core import setup
from distutils.extension import Extension
from Cython.Distutils import build_ext
sourcefiles = ['caller.pyx']
ext_modules = [Extension("caller", sourcefiles)]
setup(
name = 'test app',
cmdclass = {'build_ext': build_ext},
ext_modules = ext_modules
)
但当我尝试构建项目时,我得到了一个错误:
$ python setup.caller.py build_ext --inplace
running build_ext
cythoning caller.pyx to caller.c
Error compiling Cython file:
------------------------------------------------------------
...
cdef extern from "test.cpp":
void testFn(int arr[])
cpdef myTest(*arr):
^
------------------------------------------------------------
caller.pyx:4:6: 'myTest' is not a type identifier
在我的例子中,第二个定义不需要“cpdef”或“cdef”,通常的“def”起到了作用:
def myTest(int[:] arr):
testFn(&arr[0])
我猜你想写
myTest(int*arr)
。但这也行不通,因为int*arr
不是python对象。您不应该将其声明为python函数(cdef
而不是cpdef
),或者选择其他签名。