python-使用POST上传文件

我正在一台服务器上运行python，并希望将一些文件上载到另一台服务器。但是，当我运行python脚本时，文件不会移动到第二台服务器

第一台服务器上脚本的Python代码为：

url = 'https://www.example.com/incoming.php'

for x in list:
    if os.path.exists(x):
        filename = os.path.abspath(x) #get the full path of a file
        new_name = filename.replace('/', '_') #replace the / with _
        new_name_zip = new_name + '.zip'

        shutil.copy(x, new_name) #copy the file and give it a new name
        zippy = zipfile.ZipFile(new_name_zip, 'w', zipfile.ZIP_DEFLATED)
        zippy.write(new_name)
        os.remove(new_name) #remove the unzipped file

        uploadFile = {'uploadFile': (new_name_zip, open(new_name_zip, 'rb'))}
        r = requests.post(url, files=uploadFile)
        print (r.status_code)
        print (r.reason)

    $name=$_FILES['uploadFile']['name'];
    $size=$_FILES['uploadFile']['size'];
    $type=$_FILES['uploadFile']['type'];
    $tmp_name=$_FILES['uploadFile']['tmp_name'];
    $error=$_FILES['uploadFile']['error'];
    $location='uploads/';

    if(move_uploaded_file($tmp_name, $location.$name)) {
        $myfile = fopen("newfile.txt", "w");
        $txt = "Success\n";
        fwrite($myfile, $txt);
        fclose($myfile);
    }
?>

第二台服务器上incoming.php的代码为：

    $name=$_FILES['uploadFile']['name'];
    $size=$_FILES['uploadFile']['size'];
    $type=$_FILES['uploadFile']['type'];
    $tmp_name=$_FILES['uploadFile']['tmp_name'];
    $error=$_FILES['uploadFile']['error'];
    $location='uploads/';

    if(move_uploaded_file($tmp_name, $location.$name)) {
        $myfile = fopen("newfile.txt", "w");
        $txt = "Success\n";
        fwrite($myfile, $txt);
        fclose($myfile);
    }
?>

---

第二台服务器上的整个目录结构和所有文件都归www数据所有。在第一台服务器上运行脚本时得到的响应代码是“500 Internal server Error”。我在第一台服务器上使用了Ubuntu 18.04上的Python 2.7，在第二台服务器上使用了Ubuntu 18.04上的LAMP stack。

好的，我重新整理了代码，并使其成功运行。工作守则是：

#!/usr/bin/python3

import requests

url = 'http://example.com/receiver.php'
filename = 'file.txt'

up = {'uploadedFile':(filename, open(filename, 'rb'), 'multipart/form-data')}
r = requests.post(url, files=up)

print (str(r.status_code) + ' ' + r.reason)

服务器端的PHP代码（/var/www/html）是：